Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no significant difference between the actual and the expected genotype distributions.f) The data do not support the Hardy-Weinberg expectations - there is a significant difference between the actual and the expected genotype distributions.g) The data support Hardy-Weinberg expectations- there is a significant difference between the actual and the expected genotype distributions.h) The data do not support the Hardy-Weinberg expectations - there is nosignificant difference between the actual and the expected genotype distributions.i) Not enough information is given.

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter19: Population Genetics And Human Evolution
Section: Chapter Questions
Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...
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Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)

a) The data do NOT fit the hypothesized distribution.

b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). 

c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.

d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.

e) The data support Hardy-Weinberg expectations – there is no significant difference between the actual and the expected genotype distributions.

f) The data do not support the Hardy-Weinberg expectations - there is a significant difference between the actual and the expected genotype distributions.

g) The data support Hardy-Weinberg expectations- there is a significant difference between the actual and the expected genotype distributions.

h) The data do not support the Hardy-Weinberg expectations - there is nosignificant difference between the actual and the expected genotype distributions.

i) Not enough information is given.

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