Problem 19.70 Methanol (CH3OH) can be made by the controlled oxidation of methane: CH4 (8) + O₂(g) → CH₂OH(g) Part A Calculate AH® for this reaction. Use the following data: AH (CH₂OH(g)) Express your answer in kilojoules one decimal place. LIVE ΑΣΦ A AH° = Submit Part B AS" = Submit Request Answer Part C Calculate AS® for this reaction. Use the following data: Sp(CH₂OH(g)) = 237.6 J/(mol-K). Sp (CH4(g)) 186.3 J/(mol-K). S(O₂(g)) 205.15 J/(mol K). Express your answer in joules per kelvin to one decimal place. IVD ΑΣΦΑ Request Answer ? A & O increases O decreases Ostays the same kJ ? J/K Will AG for the reaction increase, decrease, or stay unchanged with increasing temperature? 40 of 41 Review | Constants | Periodic Table 201.2 kJ/mol. AH (CH.(g)) 74.6 kJ/mol. AH (O₂(g)) 0 kJ/mol. >

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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Problem 19.70
Methanol (CH3OH) can be made by the controlled oxidation of
methane:
CH4(g) + O2(g) → CH₂OH(g)
Part A
Calculate AHⒸ for this reaction. Use the following data: AH (CH₂OH(g))
Express your answer in kilojoules to one decimal place.
IV. ΑΣΦ
ΔΗ -
Submit
Part B
AS =
Submit
Request Answer
Part C
|VL]| ΑΣΦ 1
Calculate AS
for this reaction. Use the following data: SP (CH3OH(g)) = 237.6 J/(mol-K), Sę (CH4(g)) = 186.3 J/(mol-K).
S (O₂(g)) 205.15 J/(mol-K)
Express your answer in joules per kelvin to one decimal place.
Request Answer
O increases
IywvK ?
O decreases
Ostays the same
kJ
?
Will AG for the reaction increase, decrease, or stay unchanged with increasing temperature?
201.2 kJ/mol. AH? (CH4(g))
J/K
40 of 41
Review | Constants | Periodic Table
74.6 kJ/mol. AH (O₂(g)) = 0 kJ/mol.
Transcribed Image Text:Problem 19.70 Methanol (CH3OH) can be made by the controlled oxidation of methane: CH4(g) + O2(g) → CH₂OH(g) Part A Calculate AHⒸ for this reaction. Use the following data: AH (CH₂OH(g)) Express your answer in kilojoules to one decimal place. IV. ΑΣΦ ΔΗ - Submit Part B AS = Submit Request Answer Part C |VL]| ΑΣΦ 1 Calculate AS for this reaction. Use the following data: SP (CH3OH(g)) = 237.6 J/(mol-K), Sę (CH4(g)) = 186.3 J/(mol-K). S (O₂(g)) 205.15 J/(mol-K) Express your answer in joules per kelvin to one decimal place. Request Answer O increases IywvK ? O decreases Ostays the same kJ ? Will AG for the reaction increase, decrease, or stay unchanged with increasing temperature? 201.2 kJ/mol. AH? (CH4(g)) J/K 40 of 41 Review | Constants | Periodic Table 74.6 kJ/mol. AH (O₂(g)) = 0 kJ/mol.
F
Part D
Calculate AG at 298 K.
Express your answer in kilojoules to one decimal place.
AGO =
Submit
Part F
V—| ΑΣΦ
Part E Complete previous part(s)
Request Answer
Submit
Is there a temperature at which the reaction would be at equilibrium under standard conditions and that is low enough so that the compounds involved are likely to be stable?
Match the items in the left column to the appropriate blanks in the sentences on the right.
AG > 0
attainable
unattainable
?
AG <0
AG=0
kJ
Request Answer
Reset Help
The reaction is at equilibrium when
. To reach an equilibrium, the temperature of the
system should be so high that the reactants and products are likely to decompose. Therefore,
equilibrium is functionally
for this reaction at standard conditions.
Transcribed Image Text:F Part D Calculate AG at 298 K. Express your answer in kilojoules to one decimal place. AGO = Submit Part F V—| ΑΣΦ Part E Complete previous part(s) Request Answer Submit Is there a temperature at which the reaction would be at equilibrium under standard conditions and that is low enough so that the compounds involved are likely to be stable? Match the items in the left column to the appropriate blanks in the sentences on the right. AG > 0 attainable unattainable ? AG <0 AG=0 kJ Request Answer Reset Help The reaction is at equilibrium when . To reach an equilibrium, the temperature of the system should be so high that the reactants and products are likely to decompose. Therefore, equilibrium is functionally for this reaction at standard conditions.
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