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Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle = 35.0", a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is vy, the y-component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y t=0 Xo = 0 Yo=0 y t x =? y =? Vy =? Vy =? /a= 1.25 m/sec² L = 200 m X Vo = 0 Let's now re-define the time to t= 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. h) Re-define as t = 0 xo Yo Vox Voy - LIE |Ymax =? t =? y=0x=? X

Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle = 35.0", a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is vy, the y-component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y t=0 Xo = 0 Yo=0 y t x =? y =? Vy =? Vy =? /a= 1.25 m/sec² L = 200 m X Vo = 0 Let's now re-define the time to t= 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. h) Re-define as t = 0 xo Yo Vox Voy - LIE |Ymax =? t =? y=0x=? X

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle 0 = 35.0°, a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v₂, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is vy, the y -component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y y t = 0 Xo = 0 Yo=0 0 t x = ? y =? Vx =? Vy = ? a = 1.25 m/sec² L = 200 m Vo = 0 Let's now re-define the time to t = 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. h) What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. x Re-define as t = 0 xo Yo LIE Vox Poyr |Ymax =? t=? y = 0 x =? x
Transcribed Image Text:Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle 0 = 35.0°, a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v₂, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is vy, the y -component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y y t = 0 Xo = 0 Yo=0 0 t x = ? y =? Vx =? Vy = ? a = 1.25 m/sec² L = 200 m Vo = 0 Let's now re-define the time to t = 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. h) What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. x Re-define as t = 0 xo Yo LIE Vox Poyr |Ymax =? t=? y = 0 x =? x
-b+√b²-4ac 2a x = x₂ + V₁xt + ²axt², V₁₁x = V₁x + axt, (v₁₁x)² = (v₁x)² + 2axx, t == у = V₁ + V₁¸yt + ² α¸t², Vf₁y = V₁y+āÿt, (Vƒ‚y)² = (v₁y)² + 2a,ÿ
Transcribed Image Text:-b+√b²-4ac 2a x = x₂ + V₁xt + ²axt², V₁₁x = V₁x + axt, (v₁₁x)² = (v₁x)² + 2axx, t == у = V₁ + V₁¸yt + ² α¸t², Vf₁y = V₁y+āÿt, (Vƒ‚y)² = (v₁y)² + 2a,ÿ
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