Problem 5:An electron (q= -e = -1.60 × 10-19 C and me = 9.11 × 10-31 kg) in a cathode-ray tube isaccelerated through a potential difference of 10 kV. Thus, the electron leaves the cathode-raytube with a speed v = 5.93 × 107 m/sec. The electron then passes through the 2.0 cm wideregion of uniform magnetic field (shown in the Figure above on the right). What field strengthwill deflect the electron by 10°? Answer: B = 0.0029 T.OV10 kV2.0 cm10°

Magnetic field strength is 0.0029TExplanation:Given data:-Solution:-

Answered: Problem 5: An electron (q= -e = -1.60 ×…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

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Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 63AP: An electron of kinetic energy 2000 eV passes between parallel plates that are 1.0 an apart and kept...

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