Problem 5: Design a Non-Inverting amplifier with the voltage gain of 15V.
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Q: Vb is equal to 302∠200 and Vbc is 523.079∠230, the phase sequence is:" POSITIVE NEGATIVE
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Q: 3.19 Find V, in Fig. E8.19 using (a) nodal analysis and (b) mesh analysis. ANSWER: V, = 17.4/-21.62°…
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Q: 3. Three non-inductive resistances, each of 100 Q, are connected in star to a three- phase, 440-V…
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Q: Find lo in the network using the current division rule. Choose the cori 12 mA 32 kn 6 kn 3 kn
A: Given,
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A: Given:E=10VR=50ΩC1=0.22μFC2=2.2μFL=50mH
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- Write down the characteristics of an ideal op-amp. Design an op-amp circuit with inputs v1, v2and v3 such that v0= -3v2 + 0.5v1 + 2v2.I want the answer with details as soon as possible. Please Q-Design an op-amp circuit to amplify the AC voltage of 0.7v to become 3v , And the voltage of VCC is 5v DC.Design a circuit using op-amps for following equation. VO = 2V1 − 3V2 − 5V3 + 2V4 − 7V5 Where V1, V2, V3, V4 and V5 are input signals and VO is output signal.
- Design an op-amp circuit that meets the following specifications. Your design can be done with one or two op-amps. Your instructor may give you a different design. Note: Show all work. Draw a schematic of your design and label component values and op-amp pin numbers. a. The op-amp circuit must have a non-inverting overall voltage gain that is adjustable from +3 to +12. The circuit has a 47 k load resistor connected from the last op-amp's output terminal to ground. b. c. The circuit input resistance must be ≥ 50 kn. Your design is limited to a maximum of two op-amps and seven resistors, one of which is a variable 100 k resistor (potentiometer). The potentiometer resistance is 0 22 when adjusted to one extreme of its range and 100 k at the other extreme. d. When the potentiometer is adjusted to one extreme position the overall circuit voltage gain should be +3. When the variable resistor is adjusted to its other extreme position the overall circuit voltage gain should be +12.OAP 5 Design an op-amp circuit using a single op-amp that adds two input signals V₁1 and Vs2. That is, Vo = Vs1 + Vs2. Each input signal can vary between -5 V and +5 V: -5 V ≤ Vs1 ≤ +5 V and -5 V ≤ Vs2 ≤ +5 V. Choose resistor values such that the maximum current leaving or entering either voltage source (vs1 or Vs2) is 1 mA. (You can assume the power rails VDD and Vss are large enough to accommodate the most extreme outputs.)I already asked this once and it was answered incorrectly. Solve Vx using kcl and/or kvl and find it symbolically. The final answer should be -2A0R. Redraw the circuit as needed and explain the redrawn circuit as well. Note: it's an ideal op amp.
- (a) Design and implement the give expression from given de voltage Vdc-10v using op-amp.R2=100ohm and R1-120ohm (b) Find out the output voltage form the given expression? Vout = { [1+2*1*13.35*Vde+2.26*Vdc] } R1Q.2 Design an op-amp circuit using two inverting configurations to produce the output V.= -15V+ 5Vz+ 0.5V3- 20V4(.. ) Based on Adder-Subtractor Circuits, Design using Op- Amp to give an output voltage Vo=—5V1— 3V2+8V3 +ZV4
- The op amp in the circuit shown is ideal. What op amp circuit configuration is this?Va=3V and Vb=0V so I think that this would result in an inverting op-amp and has the equation -(160/20)*3=-24V but this is wrong I tried the long way as well but got the same answer. The possible source of error could be the 5k resistor but that doesn't make to much sense to me. How do I solve this?The DC inputs of the ideal opamp circuit given in the figure are respevtively V1=3V and V2=9V. Calculate output V0 of this circuit.