Prove that sum = i² after every iteration of the for loop below: Input: n: nonnegative integer Output: n² 1 sum= 0 2 for i=1 to n do sum = sum + 2i - 1 3 4 end 5 return sum
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- find the summation of the following series: using for loop Sum =0 + 5 + 10 + 15 + . ....+100answer with proper explanation and step by step solution. Question: Given a positive integer input n�, write a loop to compute the sum of all the odd factors of n. For example, if n� is 6, the sum should be 4, because 6 has two odd factors: 1 and 3. Sample runs Input 1: 10 Output 1: 6 Input 2: 7 Output 2: 8ckup on sum-0 while n>0: digit=n%10 print (digit) sum-sum+digit print (sum) n=n//10 print (n) Figure 5 a) Complete the trace table given below to trace the flow of execution of algorithm in Figure5 when n value is 2362. n sum O digit b) What causes the while loop to terminate ? ♫ A P
- Generate an (n X m) Addition table. Use a nested-loop. Input : n = 5 and m = 4 Output: Addition Table 1 2 3 4 2 4 5 6 3 5 6 7 4 6 7 8 5 7 8 9please code in JAVA find count. sum and find min, max using the while loop, do-while and for loop seperatelY.. write 3 different codes using all the methods to find all thoseRewrite the following for loop using while loop. Add the necessary statements if needed. for (int n-1; n<=15; n++) } System.out.printf("This is %dth iteration.", n);
- Question 1 4. Solve the following series by using while loop: y = 2/32 + 2/ 43+2/54+ ........ 2/n"-1 Question 2 Take an input from the user, if input is between 20-20, print all even numbers from 30 –40 by using for loop.create desk check table for counting looping coding that produce either the number is odd number or even number for 15 number .Provide trace table for the following loops: int s = 1; int n =1; do { s = s + n; n++; } while ( s < 10 * n);