public static int[] mergeArr ( int nums1[], int m, int nums2[], int n) { int i - 0,j int arr[] 0,k - 0; - new int[m+n]; //create a new array for merging while (i < m && j < n) { //if the current term in in first array is less than 2nd if ( nums1[i] <- nums2[j]) { arr[k++] - nums1[i++]; //add next term in nums1 to acc } else { arr[k++] - nums2[j++]; //add next term in nums2 to acc while (i < m ) { arr[k++] } while ( j

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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The code in the picture takes two sorted arrays of sizes m and n, then it merges and sorts them. Whats the best-case and worst-case for this alogrithm?

 

260 /**
* This method handles joining and sorting two arrays
@param nums1
@param m
@param nums2 - 2nd array
@param n
@return
*/
public static int[] mergeArr ( int nums1[], int m, int nums2[], int n)
{
int i - 0,j = 0,k = 0;
int arr[]
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first array
- size of first array
*
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size of 2nd array
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340
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new int[m+n]; //create a new array for merging
%3!
38
while (i < m && j < n)
{
//if the current term in in first array is less than 2nd
if ( nums1[i] <= nums2[j])
{
arr[k++] = nums1[i++]; //add next term in nums1 to arr
}
else
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{
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arr[k++] = nums2[j++]; //add next term in nums2 to acr
}
}
while (i < m)
{
arr[k++]
}
while ( j<n)
{
arr[k++]
}
return arr;
} //end mergeArr
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nums1[i++];
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= nums2[j++];|
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61 }
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Transcribed Image Text:260 /** * This method handles joining and sorting two arrays @param nums1 @param m @param nums2 - 2nd array @param n @return */ public static int[] mergeArr ( int nums1[], int m, int nums2[], int n) { int i - 0,j = 0,k = 0; int arr[] 27 28 first array - size of first array * 29 30 31 size of 2nd array 32 33 340 35 36 37 new int[m+n]; //create a new array for merging %3! 38 while (i < m && j < n) { //if the current term in in first array is less than 2nd if ( nums1[i] <= nums2[j]) { arr[k++] = nums1[i++]; //add next term in nums1 to arr } else 39 40 41 42 43 44 45 46 47 { 48 49 arr[k++] = nums2[j++]; //add next term in nums2 to acr } } while (i < m) { arr[k++] } while ( j<n) { arr[k++] } return arr; } //end mergeArr 50 51 52 53 nums1[i++]; 54 55 56 = nums2[j++];| 57 58 59 60 61 } 62
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