PURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution from the offspring genotypes. Note that the two parental gamete types (+ + and pu vg) are the most abundant, as expected. Use the data to calculate the recombination frequency and the genetic map distance between the two genes. Record the map distance in your notes.
PURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution from the offspring genotypes. Note that the two parental gamete types (+ + and pu vg) are the most abundant, as expected. Use the data to calculate the recombination frequency and the genetic map distance between the two genes. Record the map distance in your notes.
Chapter14: Human Inheritance
Section: Chapter Questions
Problem 2GP: Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect...
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Transcribed Image Text:PURPLE VESTIGIAL DIHYBRID CROSS
In the parental generation, you mate a pure-breeding wild-type female
(put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to
produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1
flies are all dihybrid.
Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males,
which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross
are:
Phenotype Genotype Tester Gamete Dihybrid Gamete Number
Wild-type
437
417
77
59
Purple, vestigial
Vestigial
Purple
Copy the table into your notes and derive the dihybrid gametes following the
example in the first section. The columns in blue (phenotypes and numbers of
offspring) are what you can see and count. The genotypes of the testcross
offspring (orange) must be deduced from the phenotypes and knowing that the
tester contributed pu vg gametes. Finally, you can deduce the dihybrid
gametes (green) by subtracting the tester gamete contribution from the
offspring genotypes.
Note that the two parental gamete types (+ + and pu vg) are the most
abundant, as expected. Use the data to calculate the recombination frequency
and the genetic map distance between the two genes. Record the map
distance in your notes.
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