pycharm. kindly pls include the py. file thanks!
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pycharm. kindly pls include the py. file thanks!
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- Given an image represented by an NxN matrix, where each pixel in the image is 4bytes, write a method to rotate the image by 90 degrees. Can you do this in place?Please draw the Olympic Rings. You can output many stars (*) to form a rings, but the parameter of the rings should be adjustable,(Please code without using Graphics . Note:there are already some answers here which are not drawing the real olympic rings without using Graphics )can you solve this please? Adopt appropriate Java animation code to implement the video in the file “test4.wmv” and given that the parametric equation for a circle. x=r*cos(t) y=r*sin(t) with t in range [0, 2p] and r is the radius of the circle. (the circle goes in a loop like in the images, i did my best to try to explain it , please try to do it ) and here is a sample of what they want me to use : package javaapplication1;import java.awt.*;import java.awt.event.*;import javax.swing.*;import java.awt.geom.*;import java.util.Random;import javax.imageio.*;import java.io.File;import java.io.IOException;import java.awt.image.BufferedImage;import java.awt.event.*;import java.util.Calendar; public class JavaApplication1 extends JApplet { public static void main(String[] args) { JFrame frame=new JFrame(); frame.setTitle("hello"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JApplet applete =new JavaApplication1(); applete.init();…
- I already saw a solution to this problem here, but it is not correct The edge-detection function (detectEdges) described in Chapter 7 and shown below returns a black and white image. Think of a similar way to transform color values so that the new image is still in its original colors but the outlines within it are merely sharpened. def detectEdges(image, amount): """Builds and returns a new image in which the edges of the argument image are highlighted and the colors are reduced to black and white.""" def average(triple): (r, g, b) = triple return (r + g + b) // 3 blackPixel = (0, 0, 0) whitePixel = (255, 255, 255) new = image.clone() for y in range(image.getHeight() - 1): for x in range(1, image.getWidth()): oldPixel = image.getPixel(x, y) leftPixel = image.getPixel(x - 1, y) bottomPixel = image.getPixel(x, y + 1) oldLum = average(oldPixel) leftLum = average(leftPixel)…JAVA SWINGI have definied a straight TUBE as: int rectWidth = 25; // replace 50 with the desired width of the rectangleint rectHeight = 200; // replace 200 with the desired height of the rectangleint rectX = (this.getWidth() - rectWidth) / 2;int rectY = (this.getHeight() - rectHeight) / 2;game.fillRect(rectX, rectY, rectWidth, rectHeight);I need L tube, which connects the straight tubes. How to define L tubes?Write a test program that creates two hexagons (5) and (10) and compares them using method compareTo(). Also, create array of four comparable hexagons with side value (4), (6), (10) and (2). Pass the array as parameter to method max. You should get the following result. Comparing two Hexagons -1 Max hexagon with biggest number of sides is 10.0
- Java problem. While out on a standard run we notice that our radar is picking up someone following us. In the hopes of losing them, we look for a nearby debris field to hide in. We notice one not too far away, but we need to make sure that we can get to the middle of the debris field to be properly hidden. Our radar shows the debris field in 2D, so we can visually check if we can make it to the center, but that takes too long. We want a program that will let us know if there is a path from the outside of the debris field to the center. In order to solve this problem, we must think recursively. Create a recursive algorithm that determines if a path exists from the outside of the debris field to the center. The debris field is always square (n by n) and n will always be greater than 1, and always odd. You can enter the debris field from any of the outside spaces, and you simply need to return true if a path exists, and false if a path does not exist. For movement you can only go up,…In Java please. Reimplement the TrafficLight class using a simple counter that is advanced in each call to next. If the traffic light was initially green, the counter has values 0 1 2 3 4 5 6 … . If the traffic light was initially red, the counter has values 2 3 4 5 6 7 8 … . Compute the current color and the number of reds, using integer division and remainder. Help me with this code (fill in /* Your code goes here */): /** A simulated traffic light.*/public class TrafficLight{ private int steps; /** Constructs a green traffic light. */ public TrafficLight() { /* Your code goes here */ } /** Constructs a traffic light. @param initialColor the initial color "green", "yellow", or "red" */ public TrafficLight(String initialColor) { /* Your code goes here */ } /** Moves this traffic light to the next color. */ public void next() { steps++; } /** Returns the current color of this traffic light. @return…Create a Java Program to make a calculator using Switch Case. If the input is not anarithmetic operator, the program will display: “You have entered wrong operator!”. See attached image for the sample output.