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- Q-1: Write a program in Assêmbly language using MIPS instruction set that will display the following pattern using nested for loops: 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 5 6 1 2 3 4 56 7Memory 12200 12201 12202 12203 12204 Content %D AA EE FF 22 What result is produced in the destination operand by execution the following instruction? a- LEA SI[DI+Bx+5] b- LDS SI.[200]Computer Science Write an assembly language program for the 8085 Microprocessor to find the smallest of the given three numbers.Input: 2230H: 3AH2231H: A3H2232H: 18HStore the result in memory location 2250H.Note: Starting Address of the Program (Mnemonic) Code: 2200H
- SP=1239H, SS=9876H, the physical address is AAAFOH Non of them 1BC06H 0AAAFH 99999H if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is 6324H O 4244H 4234H 6234H 6243H OHere is an LC-3 assembly language program: .ORIG x30e5 A LD R7, C LD R7, E LD R7, B D LD R7, A E LD R7, E HALT .END The following bit pattern is loaded into R7 by one of these instructions: 0010111111111110 What is the label (argument column) of the instruction which loads this value into R7 ?Write an instruction that uses a segment override.
- In the recursive factorial code given below, what happens if the instruction at line number 0x00400040 (addi $sp,$sp,8) is deleted by mistake from the following code? Ox00400028 fact: addi 0x0040002C 0x00400030 0x00400034 0x00400038 0x0040003C 0x00400040 0x00400044 0x00400048 L1: 0x0040004C 0x00400050 0x00400054 0x00400058 0x0040005C 0x00400060 SW SW siti beq addi ANSWER. addi jr addi jal Iw Iw $sp,$sp, -8 $ra, 4($sp) $a0, 0($sp) $t0, $a0, 1 $t0, $zero, L1 $v0, $zero, 1 $sp,$sp, 8 $ra $a0, $a0, -1 fact $a0, 0($sp) $ra, 4($sp) addi $sp,$sp,8 mult $v0, $a0,$v0 jr $ra Possible answers are as follows: a) Program enters an infinite loop and remains in the loop with the correct value stored in the vo register b) Program enters an infinite loop and remains in the loop with incorrect return value in the vo register c) Program enters an infinite loop and crashes due to memory access that exceeds the stack space d) Program will terminate properly but produce an incorrect return value in vo…Given following code: 00 9000 01 1150 02 1251 03 5300 04 6420 05 7541 06 8414 07 D20A 08 2523 09 0000 0A 3331 0B B200 0C D20A 0D 2523 0E 0000 50 000A 51 0005 52 0000 Explain what each instruction does in the program, stored in the memory locatons 00 through 0E. When the program stops, what are values in registers R0, R1, R2, R3, R4, R5, and in memory location 52? What does the program do?Convert the given hex value to its R-format MIPS instruction by completing the following table. The instruction and letters for registers must be in lower case. DO NOT TYPE DOLLAR SIGNS WITH REGISTERS. Hex Opcode (decimal) rs (decimal) rt (decimal) rd (decimal) funct (decimal) Instruction 02488822 O 18 16 17 34 sub s4 $$1 " $ to " LA
- if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is O 6243H O 4234H O 6234H O 6324H O 4244HBus d'adresse Ox0 A7 0 A6 0 AS Oxo 0 A4 0 A3 0 A2 0 A1 Lecture Bus de contrôle Écriture AO Bus de données Mémoire d'Instructions Adr Adr Ctr Ctr Ctr Ox Mémoire de données Clavier Écran CD 0 EN Data Data EN Data EN Data EN Write the instruction STR R2, [R3] in hexadecimal (using 2 bytes). АО A1 DO D1 D d u r D3 D2 09The LC-3 assembler must be able to map an instruction’s mnemonic opcode into its binary opcode. For instance, given an ADD, it must generate the binary pattern 0001. Write an LC-3 assembly language program that prompts the user to type in an LC-3 assembly language opcode and then displays its binary opcode. If the assembly language opcode is invalid, it displays an error message. Thank you in advance!