Q1) Do as required. a) Express decimal number (-123) in binary as an 8-bit sign-magnitude form. b) Add the BCD numbers: 10011000 + 10010111
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- Q3) A - Convert the Excess-3 to binary number : ( 110001011100.10001010)ex-3 B- convert each Gray code to binary: 1-( 011010001001)G 2-(59)DPerform floating point binary addition to the following: A: 1 10000011 10110111010000000000000 B: 0 10000000 10010011000100101000000 The result of A+B must be in be in 32-bit floating point. You can also check the answer in decimal.How to build this circuit? (on Digital or Logisim) Binary-coded decimal is an alternative method of representing integers using binary. In it, each base-10 digit is represented by four bits, thus each nibble takes one of 10 values (0000 through 1001). Therefore, using BCD, 42 (decimal) is represented as 0100 0010 (binary) and 196 (decimal) is represented as 0001 1001 0110 (binary). Create a circuit in Logisim that accepts as input a pair of two-digit integers represented as BCD and outputs their sum in BCD. Any and all Digital components are fair game. You can assume that all inputs will be valid BCD-encoded numbers.
- b) There are five binary or hexadecimal numbers and six decimal conversions. Draw a line to connect each binary/hexadecimal to decimal number. Binary/Hexadecimal Decimal 4E 78 11011010 157 10011101 167 A7 25 19 218Q1/The binary number ( 1011011011011.1110111001101)= ( ) in octal number *Q1. Show the implementation of 4 bit binary to gray code (shown in below table) converter using either EPROM or PLA. In Gray code only one bit changes at a time. Binary Gray code Decimal equivalent 0000 0000 1 0001 0001 0010 0011 3 0011 0010 4 0100 0110 5 0101 0111 6. 0110 0101 7 0111 0100 8. 1000 1100 1001 1101 10 1010 1111 11 1011 1110 12 1100 1010 13 1101 1011 14 1110 1001 15 1111 1000
- 6. Express the following gray code numbers as binary numhers: a) 100111100 b) 0110101 c) 10110010101 7. Express the following decimal numbers as 2421 codes: a) 168 b) 6735 c) 9021 d) 254Problem 4 1-13.* Convert the following binary numbers to their equivalent decimal values. (a) 110012 Show Procedure (b) 1001.10012 (c) 10011011001.101102Add the following BINARY NUMBERS 110000111.00011+ 110000000.11011
- Q2: Answer three of the following branches: 1. Add (01110101)2 with (00110011)2 in Decimal, Binary Octal and Hexadecimal. 2. Find (5.5)10) ^3 in binary multiplication. 3. Divide (30.25)10 by (5.5)10 in binary division. 4. Subtract (00110011): from (01110101): using Normal, I's complement and 2' complement subtraction.(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).Q1. Convert the BCD number (100001000111.1001)Bcd into its equivalent Hexa-decimal number.