a compound bar consists of circular rod of steel of 25mm diameter rigidly fixed into a copper tube of internal diameter 25mm and external diameter 40mm as shown in figure. If the compound bar is subjected to a load of 120kn find the stresses developed in the two materials MODULE NAME: STRENGTH OF MATERIALSCODE: CET102GROUP ASSIGNMENT N° IIQ1. A compound bar consists of a circular rod of steel of 25 mm diameter rigidly fixed into acopper tube of internal diameter 25 mm and external diameter 40 mm as shown in Fig. Below. Ifthe compound bar is subjected to a load of 120 kN, find the stresses developed in the twomaterials.Copper tubeSteel rodO00 SPARK4

The given area of the circular rod is given below.

Q1. A compound bar consists of a circular rod of steel of 25 mm diameter rigidly fixéd Into a copper tube of internal diameter 25 mm and external diameter 40 mm as shown in Fig. Below. I the compound bar is subjected to a load of 120 kN, find the stresses developed in the two materials. Copper tube Steel rod SPARKA

Q1. A compound bar consists of a circular rod of steel of 25 mm diameter rigidly fixéd Into a copper tube of internal diameter 25 mm and external diameter 40 mm as shown in Fig. Below. I the compound bar is subjected to a load of 120 kN, find the stresses developed in the two materials. Copper tube Steel rod SPARKA

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.3.7P: The normal and shear stresses acting on element A are 6500 psi, 17,300 psi, and 2900 psi (see the...

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Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.
The stresses on an element are sx= 1000 Psi. sy= 500 psi, and txy= 350 psi. Find the stresses acting on an element oriented at an angle 0 = 250. Show these stresses on the rotated element.
A capped cast-iron pipe is compressed by a brass rod, as shown. The mil is turned until it is just snug, then add an additional quarter turn to pre-compress the cast-iron pipe. The pitch of the threads of the bolt ap = 52 mils (a mil is one-thousandth of an inch). Use the numerical properties provided. (a) What stresses a and arwill be produced in the cast-iron pipe and brass rod. respectively, by the additional quarter turn of the nut? (b) Find the bearing stress ahbeneath the washer and the shear stress t(in the steel cap.
The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.
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A hollow, circular, cast-iron pipe (Ec =12,000 ksi) supports a brass rod (Ec= 14,000 ksi} and weight W — 2 kips, as shown. The outside diameter of the pipe is dc= 6 in. (a) If the allowable compressive stress in the pipe is S00O psi and the allowable shortening of the pipe is 0.02 in., what is the minimum required wall thickness trmm? (Include the weights of the rod and steel cap in your calculations.) (b) What is the elongation of the brass rod Srdue to both load Wand its own weight? (c) What is the minimum required clearance h?
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Two steel tubes are joined at B by four pins (dp= 11 mm), as shown in the cross section a—a in the fiaure. The outer diameters of the tubes are dAB= 41 mm and dBC= 28 mm. The wall thickness are tAB= 6.5 mm and tBC= 7.5 mm. The yield stress in tension for the steel is sy = 200 MPa and the ultimate stress in tension is ??U:= 340 MPa. The corresponding yield and ultimate values in shear for the pm are 80 MPa and 140 MPa, respectively. Finally, the yield and ultimate values in bearing R between the pins and the tubes are 260 MPa, and 450 MPa, respectively. Assume that the factors safety with respect to yield stress and ultimate stress are 3.5 and 4.5. respectively. (a) Calculate the allowable tensile force P allowconsidering tension in the tube (b) Recompute P allowfor shear in the pins.(c)Finaly, recomputed Pallowfor bearing between the pm and the tubes. Which is the tubes. Which is the controlling value value of P?