Q1.2afind the biggest interval on which theorem 3.1.1guarantees that theinitial valueproblem has aunique1(x + 5) y" + (x³²-4) y² + 17y= 2² +1² 460) = 3₂ y ₁ (0) = 69 4" (0)=6' x +I³optionsa) (-∞, -1)e) (-5,1)i) (-1,5)answervar.problem hasb find the biggest interval on whichrantees that thegunique(۱ - ره-)(efollowingsolution.i)(-5, ∞0)b) (0,5)f) (-∞, -5)j) (-5, -1) 1) (1,5)Note:c) (-∞0, 1)g) (1, -∞)1(x - 57y" + (x²-4)y" + 17y = = = = = 54(0) = 3₂ y'(0) = 6+y" (01=6+ 1Answer Optionsa) (-∞0,1)b) (1,00)f)(1,5)j) (-1,5)d) (5,00)4) (5, ∞0)4) (-1,00)theorem 3.1.1following initial valuesolution.c)(5,1)9) (-1,00)K) (-∞,5)d) (5,∞0)W)(-∞,-5)2)(-5, -1)Theorem 3.1.1Existence of a Unique SolutionLet an(x), an-1(x), ..., a₁(x), a (x), and g(x) be continuous on an interval I, and let a,(x) = 0for every x in this interval. If x= xo is any point in this interval, then a solution y(x) of theinitial-value problem (1) exists on the interval and is unique.

Answered: Image /qna-images/answer/df71e5ae-3c75-4c78-bed3-85d0dafbac67.jpg

Q1.2 find the biggest interval on which theorem 3.1.1 guarantees that the initial value problem has a unique a 1 (x + 5)y" + (x³²-4) y² + 174 = x + 1³ 4 (0)=3, y₁ (0) = 69 y" (0) = 6 options a) (-∞, -1) e) (-5, 1) i) (-1,5) answer var. problem has b find the biggest interval on which rantees that the g unique a)(-∞0,1) b) (0,5) f) (-∞, -5) j) (-5, -1) (۱ - ره-)(e i)(-5,∞0) following solution. Note: 1 (x - 57y" + (x²=-4)y" + 17y = = = = = 5 y(0) = 3₂ 41(0) = 6+9" (01-6 Answer Options c) (-∞0, 1) g) (1, -∞0) k) (1,5) b) (100) f)(1,5) j) (-1,5) d) (5,00) 4) (5, ∞0) 4) (-1,00) theorem 3.1.1 following initial value solution. c) (5,1) 9) (-1,00) K) (-∞,5) d) (5,∞0) W)(-∞,-5) 2)(-5, -1) Theorem 3.1.1 Existence of a Unique Solution Let an(x), an-1(x), ..., a₁(x), a (x), and g(x) be continuous on an interval I, and let a,(x) = 0 for every x in this interval. If x= xo is any point in this interval, then a solution y(x) of the initial-value problem (1) exists on the interval and is unique.

Q1.2 find the biggest interval on which theorem 3.1.1 guarantees that the initial value problem has a unique a 1 (x + 5)y" + (x³²-4) y² + 174 = x + 1³ 4 (0)=3, y₁ (0) = 69 y" (0) = 6 options a) (-∞, -1) e) (-5, 1) i) (-1,5) answer var. problem has b find the biggest interval on which rantees that the g unique a)(-∞0,1) b) (0,5) f) (-∞, -5) j) (-5, -1) (۱ - ره-)(e i)(-5,∞0) following solution. Note: 1 (x - 57y" + (x²=-4)y" + 17y = = = = = 5 y(0) = 3₂ 41(0) = 6+9" (01-6 Answer Options c) (-∞0, 1) g) (1, -∞0) k) (1,5) b) (100) f)(1,5) j) (-1,5) d) (5,00) 4) (5, ∞0) 4) (-1,00) theorem 3.1.1 following initial value solution. c) (5,1) 9) (-1,00) K) (-∞,5) d) (5,∞0) W)(-∞,-5) 2)(-5, -1) Theorem 3.1.1 Existence of a Unique Solution Let an(x), an-1(x), ..., a₁(x), a (x), and g(x) be continuous on an interval I, and let a,(x) = 0 for every x in this interval. If x= xo is any point in this interval, then a solution y(x) of the initial-value problem (1) exists on the interval and is unique.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.1: Tables And Trends

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