Q2 a) This is a concrete beam (the interior lines represent reinforcing bars), If P is live load, draw the BMD and the SFD as a result of ULTIMATE LOAD. P= 50 kips 20 ft. 20 ft. 40 ft. Own weight of the beam= 1.0 kip/ft. (Uniform dead load)

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Chapter5: Beams
Section: Chapter Questions
Problem 5.13.1P
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Q2 a) This is a concrete beam (the interior lines represent reinforcing bars), If P is live load, draw the BMD and the
SFD as a result of ULTIMATE LOAD.
P= 50 kips
20 ft.
20 ft.
40 ft.
Own weight of the beam = 1.0 kip/ft. (Uniform dead load)
b) This is a concrete frame (the interior lines represent reinforcing bars), If P is dead load, draw the BMD and the
SFD as a result of ULTIMATE LOAD.
6.0 ft.
P= 1.0 Kip
Own weight of the beam = 1.0 kip/ft.
(Uniform dead load)
Transcribed Image Text:Q2 a) This is a concrete beam (the interior lines represent reinforcing bars), If P is live load, draw the BMD and the SFD as a result of ULTIMATE LOAD. P= 50 kips 20 ft. 20 ft. 40 ft. Own weight of the beam = 1.0 kip/ft. (Uniform dead load) b) This is a concrete frame (the interior lines represent reinforcing bars), If P is dead load, draw the BMD and the SFD as a result of ULTIMATE LOAD. 6.0 ft. P= 1.0 Kip Own weight of the beam = 1.0 kip/ft. (Uniform dead load)
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A beam is a primary component that basically resists loads applied laterally to the beam's hub. Its method of diversion is principally by bending. The heaps applied to the beam bring about response forces at the beam's support points.

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