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- 4mm Q, 3 mm Smm FIGURE 1.1 FIGURE 1.1 shows a system of three point charges. and Q3 ) Calculate the electre potentral energy for the ystem.An electron is fired at a speed v, = 4.2 x 105 m/s and at an angle 6 = 37° between two parallel conducting plates as shown in the figure. If s = 1.8 mm and the voltage difference between the plates is AV = 99.6 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor.An electron is fired at a speed v 4.3 x 10 m/s and at an angle 8 = 39.7 between two parallel conducting plates as shown in the figure. If s 1.7 mm and the voltage difference between the plates is AV= 99.8 V, determine how close, w. the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.
- 1) Consider the figure below. An electron is fired towards a conducting plate from a distance L. The plate has a surface charge density a and a radius that is much greater than the distance L.. When the electron strikes the plate, it is measured that AK. E. 10 eV, where AK. E. Ty-To is the difference between the electron's final kinetic energy and initial kinetic energy. = a) Draw a diagram of the configuration including the co-ordinate system you have chosen. b) Write the integral equation for the work done on the electron when moving from it's initial position to an arbitrary final position, x . c) Write the integral equation for the potential difference of the system for a path that begins at the electron's initial position and ends at an arbitrary position, x. d) Determine the equation for the potential difference between the initial position of the electron and an arbitrary position, x. e) Plot the potential difference from part d) f) If the electron is initially at rest and L=…Please fill in the blanks. Suppose an electron (q equals negative e equals negative 1.6 cross times 10 to the power of negative 19 end exponent space text C end text space,m equals 9.1 cross times 10 to the power of negative 31 end exponent space text kg end text) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.Hi I'm given the diameter of the sphere is 25cm. An electric pen brought near this sphere causes a voltage of 5000 V. The distance between the sphere and the pen is 14cm. The pen itself is measured at 25cm. they want to know what is the charge on the sphere? Please break it down so I can understand. The last answer had the wrong diameter calculated into the problem and was missing what formulas they used for each problem and how they solved it in steps.
- The electric field strength at the surface of a flat negative electrode in 20° C salt water is 20 kV/m The field strength is 10 kV/m at a distance of 2.0 nm from the surface. Part A What is the electrode's surface charge density in nC/cm²? Express your answer in nanocoulombs per square centimeter. VAX 77- Submit Part B Bequest Answer co= ? What is the molarity of the salt solution? Assume the salt is NaCl Express your answer in terms of molarity. 195] ΑΣΦ nC/cm³ 2 MFile 2 Undo A2 22 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 Home Insert A B 1 Charge (C) Magnitue (N) 2 0.02 449.378 3 0.028 229.274 4 0.036 138.677 0.044 92.847 0.052 66.476 0.06 49.931 0.068 38.873 0.076 31.12 0.084 25.475 0.092 21.237 0.1 17.975 22 Paste XAY Clipboard 5 V X✓ Sheet1 Page Layout Calibri B I U- C 0.02 D Force magnitude (N) Formulas Data Review View Font 500 450 400 350 300 250 200 150 100 50 0 0 11 - AA a A V E F 0.02 5 229.274 G 138.677 92.847 0.04 Help Series1 44995ce magnitude (N) vs Distance(m) M Alignment H →= y=0.1798x2 R² = 1 0.06 Distance (m) General 0.08 $ % 98 Power (Series1) 66.47649.9338.87331.1225.47221.2377.975 J Number 0.1 K 0.12 5Part A The calcium ion Ca+ has charge +2e, so equation for the Nernst potential must have e replaced by 2e. The Nernst potential of Ca2+ +135 mV. is If the Ca+ ion concentration outside the cell is 2.0 mM, a typical value, what is its concentration inside the cell? Express your answer in terms of molarity. ΑΣφ M Cin = Submit Previous Answers Request Answer
- The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by the distance between them. When a kV voltage of 129. V is put across the plates of such a capacitor an electric field strength of 3.7- is measured. cm Write an equation that will let you calculate the distance d between the plates. Your equation should contain only symbols. Be sure you define each symbol. Your equation: d = Definitions of your symbols: kV = 3.7 cm = 129. V 00 X E ΔDiagsm i. Dingram ii. Dingram iii. Aneutal metal sphere rests upon an insulating platfomm. When the + aluminm plate is touched to the metal sphere, electrons are dzavm off the sphere and onto the alumirm plate. The aluninum plate has less encess + charge and the metal sphere now has an escess of + change. Which best describes the diagrams above If the charge on the aluminum is 0.14 C, then after contact the charge on the metal sphere will be Word Bank: charging by radiation charging by induction 0.14 0.7 charging by convection 0.07 charging by conduction 0.28 charging by friction2012hyundal genes... 2012 hyundal gene..... Figure +3.0 nC 10 cm 5.0 cm -6.0 nC . ARK Performance 1 of 1 2012 hyundai gene... Part A Submit Part B What is the strength of the electric field at the position indicated by the dot in (Figure 1)? 185] ΑΣΦΑΤΑ 2012 hyundal gene... Submit Provide Feedback Request Answer Apply - Pharmacy T... Request Answer P Pearson Kickoff N/C What is the direction of the electric field at the position indicated by the dot in (Figure 1)? Specify the direction as an angle measured clockwise from the positive z axis 196] ΑΣΦ Course Home Review I Constants Next >