Q2\ design a data base in name A then create a table in name students that has Five column (id,name,stage ,subject and mark) then Find 1.the student who has the maximum mark? 2. change the column name id to st_id? 3.The summation of student marks? 4. the student who has the maximum mark ?

Q2\ design a data base in name A then create a table in name students that has Five column (id,name,stage ,subject and mark) then Find 1.the student who has the maximum mark? 2. change the column name id to st_id? 3.The summation of student marks? 4. the student who has the maximum mark ?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Using the WideWorldDistributors database and the Sales schema create a function that takes InvoiceID as an input parameter and returns all the rows from the table InvoiceLines for the InvoiceID value passed into the function. If the result is a NULL return a zero
SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression
1-Write the syntax to insert into a relational table called students the address column references an object table called addresses that was created using an address_type. Other columns exist in the students table, but you are only inserting into the ones below. Aliases used should be the first letter of the table name, eg students would be s, addresses would be a Relational Table Name students attribute student_id attribute surname attribute address
fa table in a SQL database has a column of type `VARCHAR(100)", what does the "100" signify? a) The number of records that can be stored in the column. b) The number of unique characters that can be stored in the column. c) The maximum length of a string that can be stored in the column. d) The minimum length of a string that can be stored in the column.
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Refer to the film and inventory tables of the Sakila database. The tables in this lab have the same columns and data types but fewer rows. Write a query that lists the titles of films with the fewest rows in the inventory table. This query requires a subquery that computes the minimum of counts by film_id: SELECT MIN(count_film_id) FROM ( SELECT COUNT(film_id) AS count_film_id FROM inventory GROUP BY film_id ) AS temp_table; This subquery is provided in the template.
2. Get the Groups As new students begin to arrive at college, each receives a unique ID number, 1 to n. Initially, the students do not know one another, and each has a different circle of friends. As the semester progresses, other groups of friends begin to form randomly. There will be three arrays, each aligned by an index. The first array will contain a queryType which will be either Friend or Total. The next two arrays, students1 and students2, will each contain a student ID. If the query type is Friend, the two students become friends. If the query type is Total, report the sum of the sizes of each group of friends for the two students.
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calculate_new_balance Given a starting balance (a number), and a list of transaction tuples, calculate the final balance for an account. Transaction tuples are of the shape ("description", amount, "withdrawal") , or ("description", amount, "deposit"). The last entry in the tuple will be either "withdrawal" or "deposit". Every withdrawal decreases the balance of the account by the specified amount, and every deposit increases the balance. The return value is the new account balance, as a number. (which could be negative) Sample calls should look like: >>> calculate_new_balance(100, [("payday", 20, "deposit"), ("new shoes", 50, "withdrawal"), ("illicit winnings", 200, "deposit")])270>>> calculate_new_balance(100, [])100
Q2: Design Database for the following scenario and Write SQL queries. Create an ERD for the following scenario. Suppose there is a grocery store near your house. Following can be considered for ERD: A grocery store may have more than one employee. A grocery store has exactly one manager. The manager has one or more sales men working under him. Grocery store has more than one portion for the products. • Each product has a barcode, name, expired date. Many customers can busy many products, but each product is bought by only one customer. Each customer will get an invoice for his /her purchase. The bill invoice has an id.
C sharp Table: Student (the headers are the field names in the Students table) StudentID Name Age Gender ProgramID 791 Stephanie Brown 19 Female BCS 236 Shannon Dawn 25 Female BA 618 Geoff Berg 24 Male ARET 256 Andrew Schilling 22 Male BSC 902 Gary Sang 23 Male DAAD Note: There is a StudentDataSet with a Student table, a StudentTableAdapter, a StudentBindingSource, and a StudentDataGridView control on the form.Note: There is an Average query, named Average, that returns the average age of the student from the Student table.Note: There is also Max query, named Highest, that returns the highest age of the student from the Student table.Write the code you would place in the AverageButton click event on your form to call the Average query and the Highest query and display in a DifferenceLabel, the difference between the highest age of a student and the average age.
Create a PL/SQL database programming block with DECLARE BEGIN END; In Declare section define a local scalar (simple) variables. lv_deptno NUMBER And assign initial values as 10 lv_deptno NUMBER := 50; In Declare section again, define a cursor and select last_name, salary and manager_id of employees the ones who are working in the department defined in a) In this example department will be lv_deptno:=50; Sample code: Cursor c_emp as SELECT last_name, salary, manager_id FROM employees WHERE department_id = lv_deptno; In the execution section (BEGIN and END) Create CURSOR FOR LOOP for cursor to process In this cursor loop, your code has to check salary and also manager_id numbers each time new records being fetched. And based on these conditions either employee gets raise or not get raise. If employee salary is less than 5000 and also if employees managers is either 101 or 124 then it means employee is due for raise otherwise employee is not due for raise Sample…