Q3\ if 0001 = Load AC from memory, 0010 Store AC to memory, 0101= Add to AC from memory Where we have three memory location 500,501 and 502 the contents in first location is 1880, the contents in second location is 5881 and the contents in third location is 2881. the contents of 880 is 0002 and the contents of 881 is 00O3.DRAW a diagram that show the contents of PC,IR and AC at the end of program ?
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- OOP Programming Q5. Draw the state-of-memory diagram for the following code. 1 Account latteAcct, espressoAcct; 2 latteAcct = new Account(); 3 espressOAcct = new Account(); 4 latteAcct = espressoAcct;Interrupts are system wide events that stop the execution of a currently running process. Examples of interrupts include (but are not limited to) mouse clicks, process termination, key presses, etc. Some interrupts are considered as more important to be handled first then the others. For example, a hardware interrupt such as hard drive read operation has lesser priority than a memory read. In this way, the most appropriate data structure for representing of such events is the priority queue. Demonstrate by writing an algorithm or a flowchart how to insert the following interrupts in a heap so the highest priority element should move out first. Interrupts Priorities INT 0 100 INT 10 51 INT 11 52 INT 21 54Write the mnemonics of the following program: The pressure of two boilers is monitored and controlled by a microcomputer works based on microprocessor programming. A set of 6 readings of first boiler, recorded by six pressure sensors, which are stored in the memory location starting from 2050H. A corresponding set of 6 reading from the second boiler is stored at the memory location starting from 2060H. Each reading from the first set is expected to be higher than the corresponding position in the second set of readings. Write an 8085 sequence to check whether the first set of reading is higher than the second one or not. If all the readings of first set is higher than the second set, store 00 in the ‘D’ register. If any one of the readings is lower than the corresponding reading of second set, stop the process and store FF in the register ‘D’. Data (H): First set: 78, 89, 6A, 80, 90, 85 Second Set:71, 78, 65, 89, 56, 75
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