Q4/ The ideal gas equation of states is given by: PV = nRT Where: P is the pressure, V is the volume, T is the temperature, R=0.08206 (L atm)/(mol K) is the ideal gas constant, and n is the number of moles. Real gases, especially at high pressures, deviate from this behavior. Their responses can be modeled with the van der Waals equation: nRT using matlab V-nb P n² a + = 0 v2= Where a and b are gas constants. For Cl₂ a = 6.579 L'atm/mol², and b = 0.0562 L/mol. (a) Write a code which asks the user to insert n, T, a, b and then plots P versus V on one figure - two plots for both equations if the volume range is (0.5

Two small charged objects attract each other with a force F when separated by a distance d.If the charge on each object is reduced to one-fourth of its original value and the distance between them is reduced to d/2,the force becomes?

standard science experiment is to drop a ball and see how high it bounces. Once the “bounciness” of the ball has been determined, the ratio gives a bounciness index. For example, if a ball dropped from a height of 10 feet bounces 6 feet high, the index is 0.6, and the total distance traveled by the ball is 16 feet after one bounce. If the ball were to continue bouncing, the distance after two bounces would be 10 ft + 6 ft +6 ft + 3.6 ft = 25.6 ft. Note that the distance traveled for each successive bounce is the distance to the floor plus 0.6 of that distance as the ball comes back up. Write a program that lets the user enter the initial height from which the ball is dropped, the bounciness index, and the number of times the ball is allowed to continue bouncing. Output should be the total distance traveled by the ball.

Given two particles with Q = 4.30-µC charges as shown in the figure below and a particle with charge q = 1.39 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = co.) x = -0.800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 4.30-µC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 4.30-pC particles? (Enter the magnitude.) V N/C (c) What is the electrical potential (in kV) at the origin due to the two 4.30-uC particles? 96.75 V kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge g were moved a distance d = 0.400 m closer to either of the 4.30-µC particles?

A damper (or dashpot) is connected to the mass M of the previous problem. This could represent air resistance. The entire system could be a simple model of an automobile wheel suspension system (assuming the automobile body immobile in a vertical direction). Then the damper acts as a shock absorber. As before, the system is displaced and released and x(tg) = x, and v(to) = vo - It can be shown that the motion of the system Is described by the following differential equation: Mx + Dx + Kx(t) = 0 where D is the damping factor of the dashpot and x = v(t) = velocity at time t. Model and simulate the motion of the system from timet= to to t= tf, using a digital computer program, FIG. 1 DAMPER 3 SPRING FIG.I M MASS

The voltage V(1) (in V) and the current i(t) (in Amp) t seconds after closing the switch in the circuit shown are given by: R Vdt) = V(1– e/) i(t) = e, where t, = RC is the time constant. Consider the case where V = 24 V, R = 3800 2 and C = 4000 x 10-6 F. Determine the voltage and the current during the first 20 s after the switch is closed. Create a vector with values of times from 0 to 20 s with spacing of 2 s, and use it for calculating V(1) and i(t). Display the results in a three-column table where the values of time. voltage and current are displayed in the first, second, and third columns, respectively. (To display values in a Table, just create matrix and have its output displayed) Script ® C Reset I MATLAB Documentation 1 %Don't change the variable name 2 table =

What is the most simplified expression of the following Karnaugh map?

QI: Prove that: (x.Y.z) + (X.Y). (X.Z) = X+Y.Z?

2. calculates the trajectory r(t) and stores the coordinates for time steps At as a nested list trajectory that contains [[xe, ye, ze], [x1, y1, z1], [x2, y2, z2], ...]. Start from time t = 0 and use a time step At = 0.01; the last data point in the trajectory should be the time when the oscillator "hits the ground", i.e., when z(t) ≤ 0; 3. stores the time for hitting the ground (i.e., the first time t when z(t) ≤ 0) in the variable t_contact and the corresponding positions in the variables x_contact, y_contact, and z_contact. Print t_contact = 1.430 X_contact = 0.755 y contact = -0.380 z_contact = (Output floating point numbers with 3 decimals using format (), e.g., "t_contact = {:.3f}" .format(t_contact).) The partial example output above is for ze = 10. 4. calculates the average x- and y-coordinates 1 y = Yi N where the x, y, are the x(t), y(t) in the trajectory and N is the number of data points that you calculated. Store the result as a list in the variable center = [x_avg, y_avg]…

The displacement of an oscillating spring can be described by x = A cos(wt) where x = displacement at time t, A = maximum displacement, w = angular frequency, which depends on the spring constant and the mass attached to the spring, and t = time.   Find the displacement, x, with maximum displacement A of 4 cm, for times from 0 to 120 seconds with increments of 30 seconds, and angular frequencies from 0.4 to 0.6 radians/sec, with increments of 0.1 radians/sec.  The displacement for all combinations of times and angular frequencies needs to be calculated. Use meshgrid. Display your results in a matrix with angular frequencies along the top row and times along the left column like so (you may put zero, 0, or NaN, in the upper left corner: