QI/Fill (5) the following blanks: 1. IPV4 are bits in length; this gives maximum of addresses. 2. The binary notation of 117.149.29.4 is 3. Network Address is 4. The subnet consists of two distinet components: and
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- Assume the maximum transmission unit (or MTU) of an IP packet on 100 Mbps Ethernet is set at 1500 bytes. Also, assume we are sending our file using IPv6 at the Network layer and UDP at the Transport layer. A typical IPv6 header consists of 40 bytes, a UDP header consists of 8 bytes. Answer the following three questions based on the information provided above. For all answers, enter a decimal integer value without formatting (no commas). 1. How many packets do we have to send in order to transfer a file of 24KB over 100 Mbps Ethernet? packets 2. How many bytes do we have to send at the network layer in order to transfer the above file entirely? bytes 3. How many bytes do we have to send at the data link layer in order to transfer the above file entirely? Assume that the Ethernet header is 14 bytes and the frame checksum is 4 bytes. bytesExplain CIDR IP allocation technique with IP Block 192.168.1.0/24. A network of size 248 computers needs to be divided into four network segments of 126, 62, 30 & 30 computers.Given the following topology of a network, the router Node 3 connects the two subnets together: Nodes 1 and 2 are 'inside' of the subnet neta, Nodes 4 and 5 are 'outside' of neta and Node 3 with a firewall is the gateway of neta. The two networks have the prefix 192.168 as the first two octets in their IP addresses, e.g, Node 1 has IP address 192.168.1.11. eth1: 1.11 eth1: 2.21 1 2 eth1: 1.12 neta eth 1: 1.1 3 eth2: 2.1 netb 4 5 eth1: 2.22 (i) Suppose in the firewall on Node 3 the default policy is ACCEPT. Write packet filtering rules for the following goal. Suppose Node 5 hosts a web server supporting both HTTP and HTTPs. Set rules in Node 3 that prevents Node 2 from browsing any web pages at Node 5. Now change in Node3 the default policy as DROP and write packet filtering rules for the following goal. (ii) Allow all nodes in the subnet neta to browsing HTTP pages hosted at Node 5. (iii) Allow hosts in netb to SSH into Nodel.
- Cisco Router A Network with id: 192.168.0.0 and subnet mask 255.255.0.0 is given to you to split it in such a way that the following classrooms are given adequate number of IPs based on their needs. Each classroom will occupy its own subnet. The following information for each subnet must be included: Subnet ID CIDR Subnet Mask First IP usable in the subnet Last IP usable in the subnet Broadcast IP Address for the subnet Classroom1: 8 PCsClassroom2: 400PC and 4 PrinterClassroom 3: 2 PCsClassroom4: 62 PCs and a ServerClassroom5: 24PCs44- An organization currently requires 40 hosts for its sales department. Given the IP Address 194.12.1.0 /24, design an optimal address scheme usingTradition Subnetting method, which will enable the connection of the sales department’s 40 hosts in one subnet and uses the remaining subnets for other departments’ hosts in the future. What will be the total number of usable (assignable) addresses per subnet? Select one: A. 62 B. 65 C. 63 D. 64For IP address: 175.30.101.205, use the provided version of the subnet mask to calculate the: slash notation binary subnet mask dotted decimal subnet mask Increment Network ID Broadcast ID Host Range Complete the Increment by determining the value of the last network bit for the given subnet mask. It is easiest to observe in the binary representation. Since network IDs will always be multiples of the increment (after the zero subnet) – in the octet that holds the last network bit, use the increment to determine the network ID, broadcast, and host range for the IP address displayed above
- Write a Java TCP Client-Server Program for Currency Converter as shown below. () CLIENT SERVER IP Address: 128.36.69.6 Domain Name. CurrencyConveret Port : 2834 NOTE Server Details are in the above figure > Client-Server communicates continuously until the Client send Bye to the Server NOTE: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Sample Output: Client From Server Present Currency Rates: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Server Server Waiting for the Cline to be Connected... CONECTION ESTABLISHED Received From Client : 10 SAR Received From Client: BYE Enter currency in SAR or BYE to EXIT: 10 Received from Server : 10 SAR = 2.6 USD (US Dollar) 10 SAR = 2.4 EUR (Euro) 10 SAR = 2.0 GBP (British Pound) 10 SAR = 17.3 CNY (Chines Yuan) Enter currency in SAR : BYE Received from Server: Thank You For Using My Program Client DISCONNECTED/Questions on the Computer Network I Q1/ Assume you have the IP address 220.254.255.x / 28. Finish the class and evaluate the subnetting to determine the mask address, number of subnets, addersses range of subnets, and number of hosts at each subnet. Q2/ How can the OSI model's encapsulation procedure be performed for the sender, and what happens to the encapsulated data at the receiver side, explain and show a graph of that? Q3/ Discuss the benefits and drawbacks of shielding copper cables.Q1. ii)Describe the four abstraction Layers of TCP/IP ii) Describe a typical scenario involving 2 computer devices transferring a video file using an unsecured ftp connection where TCP three-way handshake is susceptible to vulnerabilitiy
- 42, Which of the following statements about IPv6 are correct? A. IPv6 address 2001:0DB8:0000:0000:032A:0000:0000:2D70 can be abbreviated as 2001:DB8:0:0:32A::2D70. B. A link-local address (LLA) is a private IPv6 address that can be used only on the intranet. Because LLAS cannot be routed on the IPv6 public network, they cannot be used to directly access the public network. C. IPv6 addresses are classified into unicast, multicast, and broadcast addresses by IPv6 address prefix. D. IPv6 does not use ARP for address resolution. Instead, it uses ICMPv6 NS and NA packets to replace the address resolution function provided by ARP in IPv4.1/ 2 100% Name: Student ID: 1. Given an IP address 198.98.10.0/24, design two different addressing schemes (fixed-length and variable-length subnetting) for eight departments in an organisation as shown in the following with different number of hosts required in each department. Department Manufacturing 1 Manufacturing 2 Training 1 Training 2 Number of Hosts 25 25 10 10 Finance 10 Sale 10 Marketing Administration Fill in the following two tables showing subnet mask (or CIDR), subnet address, broadcast address and range of available host addresses in each subnet. Verify which addressing scheme is efficient in saving IP addresses Fixed-length subnetting Department Subnet mask (CIDR) | Subnet address Host add. range | Broadcast add. Manufacturing Manufacturing 2 Training 1 ENG INTL 2 DELL Delete PrtScr Insert F10 F11 F12 F9Registration Number: 193046 Consider a network with 3 hosts and a NAT router. Suppose that the network address of the home network is 192.168.NNN/24, where NNN are the last 3 digits of your Reg#. For example, if your Reg# is BSE193046, NNN = 046 and therefore the network address wil be 192168.46/24. (If NNN>255, consider NNN=254) (a) Assign any public IP address to NAT router’s outgoing interface. (b) Assign IP addresses to all 3 hosts and local interface of the NAT router in the home network. (