QUESTION 4 Calculate the AH for the reaction: C2H40(g) + H2O(1l) –→ C2H6O2(1) given: 2C2H40(g) + 502(g) → 4CO2(g) + 4H2O (1) AH=-2612 kJ C2H602(1) + 5/202(g) → 2C02(g) + 3H2O (1) AH=-1190 kJ

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.61PAE: 4.61 What is actually measured by the octane ratings of different grades of gasoline?
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QUESTION 4
Calculate the AH for the reaction:
C2H40(g) + H20(1) → C2H602(1)
given:
2C2H40(g) + 502(g)
C2H6O2(0) + 5/202(g)
4CO2(g) + 4H2O (1) AH=-2612 kJ
2C02(g) + 3H2O (1) AH=-1190 kJ
Transcribed Image Text:QUESTION 4 Calculate the AH for the reaction: C2H40(g) + H20(1) → C2H602(1) given: 2C2H40(g) + 502(g) C2H6O2(0) + 5/202(g) 4CO2(g) + 4H2O (1) AH=-2612 kJ 2C02(g) + 3H2O (1) AH=-1190 kJ
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