Homework Help is Here – Start Your Trial Now!
Math
Calculus
Question 9: Using the fact that i²= -1 and the identities: and cos(x)=(-1)" x2n (2n)!' n=0 x2n+1 sin(x)=(-1)" (2n+1)!' n=0 show that z = reio =rcos + ir sin 0.

Question 9: Using the fact that i²= -1 and the identities: and cos(x)=(-1)" x2n (2n)!' n=0 x2n+1 sin(x)=(-1)" (2n+1)!' n=0 show that z = reio =rcos + ir sin 0.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section: Chapter Questions
Problem 22RE
See similar textbooks
icon
Related questions
Question
Question 9: Using the fact that 2-1 and the identities: cos(x) = (-1)" n=0 x2n (2n)!' and sin(x): = Σ(-1)" - n=0 x2n+1 (2n+1)!' show that z=re₁ = r cos + ir sin 0.
Transcribed Image Text:Question 9: Using the fact that 2-1 and the identities: cos(x) = (-1)" n=0 x2n (2n)!' and sin(x): = Σ(-1)" - n=0 x2n+1 (2n+1)!' show that z=re₁ = r cos + ir sin 0.
Expert Solution
steps

Step by step

Solved in 4 steps with 6 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
SEE MORE TEXTBOOKS