Question: If vs(t)= 0.01 sinot, calculate id (t) by using Modified Ideal Diode Model (V-0.7V) (n=1, V-=25mV) v;(t) Vs=5V Vs=5V IK I 1K w VRI 2K 2K m1 n=1 io(t)= Ip+ io(t) 0.7 V 0.7V Step 1: D.C. Analysis Small signal sources are removed. KVL VR2=0.7 + 0.7 = 1.4 V VR2 I₂= = 0.7mA 2 VR1=5.0-VR2 = 5.0-1.4 = 3.6 V I₁-V₁-3.6 mA R1 = = IDI₁-I₂=2.9mA www.

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question: If vs (t)= 0.01 sinot, calculate id (t) by using Modified
Ideal Diode Model (V-0.7V) (n=1, V+-25mV)
v;(t)
Vs=5V
Vs= 5V
I
1K
Ww
1K
2K
VRI-
2K
VR₂
FF1
n=1
io(t)= Ip+ i(t)
I
0.7 V
0.7V
Step 1: D.C. Analysis
Small signal sources are removed.
KVL VR2 = 0.7 +0.7 = 1.4 V
I₂ = -0.7mA
2
VR1=5.0-VR2=5.0-1.4 = 3.6 V
R2
=
I₁ = V2₁
R1
1
ID = I₁-1₂-2.9mA
=
= 3.6 mA
Transcribed Image Text:Question: If vs (t)= 0.01 sinot, calculate id (t) by using Modified Ideal Diode Model (V-0.7V) (n=1, V+-25mV) v;(t) Vs=5V Vs= 5V I 1K Ww 1K 2K VRI- 2K VR₂ FF1 n=1 io(t)= Ip+ i(t) I 0.7 V 0.7V Step 1: D.C. Analysis Small signal sources are removed. KVL VR2 = 0.7 +0.7 = 1.4 V I₂ = -0.7mA 2 VR1=5.0-VR2=5.0-1.4 = 3.6 V R2 = I₁ = V2₁ R1 1 ID = I₁-1₂-2.9mA = = 3.6 mA
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