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R = 0.08205 L atm mol-1 K-1 T(K) = T (°C) + 273.15 1 atm = 101,325 Pa = 1.01325 bar Calculate the density (in g/L) of Oz (MW = 31.9988) at 415 K and 310 bar using the van der Waals equation of state. 3 sig figs a = 1.382 dm bar mol-² b = 0.0319 dm³ mol-¹

R = 0.08205 L atm mol-1 K-1 T(K) = T (°C) + 273.15 1 atm = 101,325 Pa = 1.01325 bar Calculate the density (in g/L) of Oz (MW = 31.9988) at 415 K and 310 bar using the van der Waals equation of state. 3 sig figs a = 1.382 dm bar mol-² b = 0.0319 dm³ mol-¹

Physical Chemistry
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter1: Gases And The Zeroth Law Of Thermodynamics
Section: Chapter Questions
Problem 1.39E
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R = 0.08205 L atm mol-1 K-1 T(K) = T (°C) + 273.15 1 atm = 101,325 Pa = 1.01325 bar Calculate the density (in g/L) of O₂ (MW = 31.9988) at 415 K and 310 bar using the van der Waals equation of state. 3 sig figs a = 1.382 dm bar mol-² b = 0.0319 dm³ mol-¹
Transcribed Image Text:R = 0.08205 L atm mol-1 K-1 T(K) = T (°C) + 273.15 1 atm = 101,325 Pa = 1.01325 bar Calculate the density (in g/L) of O₂ (MW = 31.9988) at 415 K and 310 bar using the van der Waals equation of state. 3 sig figs a = 1.382 dm bar mol-² b = 0.0319 dm³ mol-¹
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