r STARTING AMOUNT X E According to the balanced reaction below, calculate the quantity of moles of NO₂ gas that forms when 5.20 x 103 mol of N₂Os gas completely reacts: ADD FACTOR x( ) 1.30 x 103 5.20 x 10³ 0.0208 0.0104 g NO₂ 2 Question 44 of 47 N₂Os(g) → 108.02 mol NO₂ 1 4 NO₂(g) + O₂(g) 1.57 x 10²1 g 0₂ 2 ANSWER 2.60 x 103 g N₂O5 4 46.01 mol O₂ RESET 5 6.022 x 1023 32.00 6.26 x 1021 mol N₂O5

World of Chemistry
7th Edition
ISBN:9780618562763
Author:Steven S. Zumdahl
Publisher:Steven S. Zumdahl
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 55A
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C Firefox
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(₂
C
File
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STARTING AMOUNT
B
Aktiv Chemistry
A
History
X
Bookmarks Tools
X
O8 https://app.101edu.co
=
FEB
13
Window
Aktiv Chemistry
ADD FACTOR
x( )
Help
According to the balanced reaction below, calculate the quantity of moles of NO₂ gas
that forms when 5.20 x 103 mol of N₂O5 gas completely reacts:
1.30 x 103 5.20 × 10³
0.0208 0.0104
O
X
g NO₂
S
+
Question 44 of 47
2 N₂O5(g) → 4 NO₂(g) + O₂(g)
108.02
mol NO₂
1
g 0₂
ANSWER
2
1.57 x 1021 2.60 x 103 6.022 x 1023
g N₂O5
ali
4
46.01
RESET
mol O₂
52
32.00
6.26 x 10²1
mol N₂O5
tv W
C
Transcribed Image Text:C Firefox ● (₂ C File Edit View STARTING AMOUNT B Aktiv Chemistry A History X Bookmarks Tools X O8 https://app.101edu.co = FEB 13 Window Aktiv Chemistry ADD FACTOR x( ) Help According to the balanced reaction below, calculate the quantity of moles of NO₂ gas that forms when 5.20 x 103 mol of N₂O5 gas completely reacts: 1.30 x 103 5.20 × 10³ 0.0208 0.0104 O X g NO₂ S + Question 44 of 47 2 N₂O5(g) → 4 NO₂(g) + O₂(g) 108.02 mol NO₂ 1 g 0₂ ANSWER 2 1.57 x 1021 2.60 x 103 6.022 x 1023 g N₂O5 ali 4 46.01 RESET mol O₂ 52 32.00 6.26 x 10²1 mol N₂O5 tv W C
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