RAM PROCESS 1 PROCESS 2 PROCESS 3 PROCESS 4 Operating tem 800K B) 400K+50 C) 100K+50 +1 D) 200K-50 FI 700K 50 700K 400K 200K 100K 0 144) Processes and their memory partitions are shown in the figure. If the process 4 is running and calling an instruction whose absolute address is 50, what is the physical address of this instruction produced by the memory manager? BU SORUNUN ÇÖZÜMÜNÜ ANLATABILIRMISINIZ? TURKÇE OLARAK? Toplama işlemi yapıyoruz process 4 ün en alt değerini alıp soruda verdiği değerle topluyoruz A) 50

RAM PROCESS 1 PROCESS 2 PROCESS 3 PROCESS 4 Operating tem 800K B) 400K+50 C) 100K+50 +1 D) 200K-50 FI 700K 50 700K 400K 200K 100K 0 144) Processes and their memory partitions are shown in the figure. If the process 4 is running and calling an instruction whose absolute address is 50, what is the physical address of this instruction produced by the memory manager? BU SORUNUN ÇÖZÜMÜNÜ ANLATABILIRMISINIZ? TURKÇE OLARAK? Toplama işlemi yapıyoruz process 4 ün en alt değerini alıp soruda verdiği değerle topluyoruz A) 50

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 2PE: If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the...

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The memory unit of a computer has 1M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 6 addressing modes; a register address field to specify one of 28 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: a) How large must the mode field be? b) How large must the register field be? c) How large must the address field be? d) How large is the opcode field?
Q2. For the following assume that values A, B, C, D, E, and F reside in memory. Also assume that instruction operation codes are represented in 6 bits, memory addresses are 64 bits, data size is 32 bits and register addresses are 5 bits. a. For each instruction set architecture shown in Figure A.1, how many addresses or names (including both memory and register), appear in each instruction for the code to compute C = A+ B, and what is the total code size? passor TOS Memory (A) Accumulator (C) Registry (D) Re loed oore Figure A.1 Operand locations for four instruction set architecture classes. The arrows indicate whether the oper and is an input or the result of the orithmetic-logical unit ALU operation, or both an input and result Lighter shoes indicate inputs, and the dark shode indicates the result in a top of stack (TOS) register points to the top input operand, which is combined with the operand below. The first operand is removed from the stack, the result takes the place of the…
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Part 1: Registers of Different Sizes Registers are fast, but small memory locations that are inside of a CPU. They are used for the CPU's internal computations. A modern 32-bit CPU only contains 8 registers that we are capable of manipulating: EAX, EBX, ECX, EDX, EBP, ESP, ESI, and EDI. Each of these is a 32-bit register (meaning they each hold 32 digit binary numbers). There are many situations where we would want to use smaller portions of data than 32 bits. For example, when working with characters we are primarily using byte data, since each character is stored in just a single byte (which you should know is 8 bits). For this purpose, portions of the 32-bit registers can be referenced directly as if they were smaller registers. The register EAX holds 32-bits. The register AX is the bottom half of EAX, holding just 16 bits. The register AL is the bottom half of AX, holding just 8 bits. There is also AH, which is the top half of AX and also holds 8 bits. EBX, ECX, and EDX can also be…
Part 1: Registers of Different Sizes Registers are fast, but small memory locations that are inside of a CPU. They are used for the CPU's internal computations. A modern 32-bit CPU only contains 8 registers that we are capable of manipulating: EAX, EBX, ECX, EDX, EBP, ESP, ESI, and EDI. Each of these is a 32-bit register (meaning they each hold 32 digit binary numbers). There are many situations where we would want to use smaller portions of data than 32 bits. For example, when working with characters we are primarily using byte data, since each character is stored in just a single byte (which you should know is 8 bits). For this purpose, portions of the 32-bit registers can be referenced directly as if they were smaller registers. The register EAX holds 32-bits. The register AX is the bottom half of EAX, holding just 16 bits. The register AL is the bottom half of AX, holding just 8 bits. There is also AH, which is the top half of AX and also holds 8 bits. EBX, ECX, and EDX can also be…
QuedT: Choose the correct answer: [ Opcode, funct3 and funct7/6 in instruction format are used to identify the: (a) function. (b) instruction. (e) branch. (d) memory address. The register that hold the address of the current instruction being executed is called: (a) saved register. (b) global pointer. (e) stack pointer. (d) program counter. Placing the executable file into the memory for execution by the processor is the role of (a) assembler. (b) linker. (e) loader. (d) compiler. The part which responsible for transmitting the data to/from the processor is: (a) control unit. (b) Datapath. (c) data bus. (d) memory. Parallel hardware cannot be used for faster division because: (a) subtraction is conditional on sign of remainder. (b) multiplication is conditional on sign of remainder. (c) subtraction is conditional on sign of divisor. (d) multiplication is conditional on sign of divisor. we cannot slower the clock cycle to fit the floating-point adder algorithm into one clock cycle…
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