(References) The blood alcohol CH; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion ( Cr2 O72) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2 (aq) + C,H;OH(aq) → Cr* (aq) + CO2(g) If 17.82 mL of 0.0666 M potassium dichromate solution is required to titrate 12.4 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent = Submit Answer Try Another Version 5 item attempts remaining

(References) The blood alcohol CH; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion ( Cr2 O72) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2 (aq) + C,H;OH(aq) → Cr* (aq) + CO2(g) If 17.82 mL of 0.0666 M potassium dichromate solution is required to titrate 12.4 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent = Submit Answer Try Another Version 5 item attempts remaining

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 109AE: The blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with an...

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