S Figure P1.16 shows the stress-strain relations of metals A and B during ten-sion tests until fracture. Determine the following for the two metals (show allcalculations and units):a. Proportional limitb. Yield stress at an offset strain of 0.002 m/m.c. Ultimate strengthd. Modulus of resiliencee. Toughnessf. Which metal is more ductile? Why?900Metal A600Metal B3000.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14Strain, m/mFIGURE P1.16Stress, MPa

a). Proportional Limit : The proportional limit is the point up to which the stress-strain curve is…

Answered: S Figure P1.16 shows the stress-strain…

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter6: Introduction To Mechanical Properties

Section: Chapter Questions

Problem 6.19P

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The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.
Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2 at an engineering strain of 6.0. Assume that the deformation is all elastic.
Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 000 -Metal A S 600 -Metal B 300 0.00 a.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, mim FIGURE P1.16 Stress, MPa
The shown figure represents the stress-strain relations of metals A and B during tension tests until fracture.Determine the following for the two metals (show all calculations and units):a. Proportional limitb. Yield stress at an offset strain of 0.002 in./in.c. Ultimate strengthd. Modulus of resiliencee. Toughnessf. Which metal is more ductile? Why?
1.17 Figure P1.17 shows the stress-strain relations of metals A and B during tension tests until fracture. Determine the following for the two metals (show all calcu- lations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 in./in. 150 - - Metal A 100 • Metal B 50 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, in./in. FIGURE P1.17 c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? Stress, ksi
Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness I. Which metal is more ductile? Why? 900 -Metal A E 600 Metal B 300 0.00 a02 004 a.06 0.08 0.10 0.12 014 Strain, matm FIGURE P1.16 Strees, MPa
In the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Og = -90 MPa and the initial temperature %3D 20°C. 2) The final length of the aluminium member. Aluminum A=1800mm? Bronze A=1500mm? E=73GPA E=105GPA a=23.2x10-6/°C a=21.6x10-6/°C Gap=0.5mm 0.35m 0.45m
The following information about the o-e curve is given for a steel alloy. E = 0.001527 at o = 300 MPa and ɛ = 0.003054 for o = 600 MPa. (a) Draw the stress-strain diagram and calculate the E for this alloy.

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