Section 1.8 In Exercises 1-4, solve the given initial-value problem. (For Exercise 3, you may "complexify" the problem, if you wish!) dy dy 2. - 2y = 3e-2t dt dy 3. + 3y = cos(2t) dt dy 4. - 2y = 7e2t 1. + 2y = e'/3 dt y(0) = 1 dt y(0) = 10 y(0) = -1 y(0) = 3

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