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- An operating system uses Shortest Remaining Time first (SRT) process scheduling algorithm. Consider the arrival times and execution times for the following processes: Process Execution time Arrival time P1 20 P2 25 15 P3 10 30 P4 15 45 What is the total waiting time for process P2?Let the processes P1, P2, P3, and P4 be given. They arrive in the system at the same time in this order. The processes have the following service times (in time units): Process Service time (CPU burst) exe P1 53 und P2 17 P3 68 P4 all 24 ur ca ulations. TOU arts. For the scheduling method "Round Robin" (RR), specify the average execution time (average turnaround time) and the number of context switches. The time quantum q is set to 20 time units. You must show your calculations. You will not have to draw Gantt charts. Note: For RR, processes execute in order of their ID (i.e., P1-P2-P3-P4).Fill in blank Suppose that there is only one CPU and we have three processes P1, P2, P3 arrived for execution at time 0, 1, 2 respectively. Their burst time are 8, 5, 2 respectively. None of these processes will perform I/O operations. Consider non-preemptive scheduling. With the FCFS scheduling algorithm, the average turnaround time of these processes will be----- and the average response time will be ------ With the SJF scheduling algorithm, the average turnaround time of these processes will be ----- and the average response time will be -----
- Given the list of processes, their CPU burst times, arrival times and priorities implement SJF,Priority and Round Robin scheduling algorithms on the processes with preemption. For each ofthe scheduling policies, compute and print the completion Time(CT), Turnaround Time(TAT),and Waiting Time(WT) for each process using C Programming.Waiting time: Processes need to wait in the process queue before execution starts and inexecution while they get preempted. Turnaround time: Time elapsed by each process to get completely served. (Difference betweensubmission time and completion time).Q 6:- an operating system uses SJF scheduling algorithm for preemptive scheduling of processes, consider the following set of processes, with their arrival times and length of the CPU burst times given in milliseconds and the priority of each process: Process Arrival Time Burst Time priority PO 1 5 1 P1 3 2 P2 1 P3 7 2 P4 2 1An operating system uses Shortest Remaining Time first (SRTF) process scheduling algorithm. Consider the arrival time and burst times for the following processes Process Burst Time Arrival Time P₁ 10 0 P₂ 8 4 P3 15 2 P4 4 6 What is the waiting time of the process P3(answer up to 1 decimal place)?
- Let the processes P1, P2, P3, and P4 be given. They arrive in the system at the same time in this order. The processes have the following service times (in time units): Process Service time (CPU burst) P1 53 P2 17 P3 68 P4 24 2) For the scheduling method "Round Robin" (RR), specify the average execution time (average turnaround time) and the number of context switches. The time quantum q is set to 20 time units. You must show your calculations. You will not have to draw Gantt charts. Note: For RR, processes execute in order of their ID (i.e., P1-P2-P3- P4).In a timesharing OS we have the following cpu timeline for two tasks X and Y. The timeslice is 1s.Both tasks are available in the system at the same time t=9:00:00.000 and order of arrival is the obviousX followed by Y. (The decimals reflect milliseconds if they showup in an indicated time reference.) There are no other processes (tasks) in the system other than X,Y. 1234567890 XYXYX--YXY The time line 1 indicates that at t=9:00:00s task X starts its execution and when t=9:00:01s is reached task Y takes over. The time line 1 indicates the 'first second' and time line 0 indicates the 'tenth second' above.Task Y completes its execution at t=9:00:10s, the completion of the tenth second since X started its execution. Task X has completed its execution earlier. (a) What is the total number of context switches starting from prior to t=9:00:00s (e.g. t=8:59:59.999) through thecompletion of $Y$? answer is 16s (b) What is the turnaround time for Y? answer is 10s (c) What is…Consider the following set of processes, the length of the CPU burst time given in milliseconds: Process Burst time: P1 6 P2 8 P3 7 P4 3 Assuming the above process being scheduled with the SJF scheduling algorithm: The waiting time for process P1 is 3ms. The waiting time for process P1 is 0ms. The waiting time for process P1 is 16ms. The waiting time for process P1 is 9ms.
- true/false Consider a group of CPU-time sharing processes P1 , P2, ... Pn with CPU burst times of 1,2,...,n units respectively arrive at the same time. The average waiting time of these processes is always less than n2/6 (regardless of scheduling algorithm)Consider the following set of processes, with the length of the CPU burstgiven in milliseconds:Process Burst Time PriorityP1 3 3P2 5 1P3 1 5P4 7 4P5 3 2The processes are assumed to have arrived in the order P1, P2, P3, P4, P5,all at time 0.a. Draw four Gantt charts that illustrate the execution of theseprocesses using the following scheduling algorithms: FCFS, SJF,nonpreemptive priority (a larger priority number implies a higherpriority), and RR (quantum = 1).b. What is the turnaround time of each process for each of thescheduling algorithms in part a?c. What is the waiting time of each process for each of these schedulingalgorithms?d. Which of the algorithms results in the minimum average waitingtime (over all processes)?The following processes are being scheduled using a preemptive, round- robin scheduling algorithm. 5.5 Process Priority Burst Arrival P1 P2 P3 P4 P5 P6 40 20 30 25 25 30 25 30 60 100 105 35 15 10 10 10 Each process is assigned a numerical priority, with a higher number indi- cating a higher relative priority. In addition to the processes listed below, the system also has an idle task (which consumes no CPU resources and is identified as Piale). This task has priority 0 and is scheduled when- ever the system has no other available processes to run. The length of a time quantum is 10 units. If a process is preempted by a higher-priority process, the preempted process is placed at the end of the queue. Show the scheduling order of the processes using a Gantt chart. a. b. What is the turnaround time for each process? C. What is the waiting time for each process? d. What is the CPU utilization rate?