Shear Panels - transmit shear stresses Spar Caps Rods - Carry Tension and Compression Loads

TRUE OR FALSE ? QUESTION : For a bolt pattern in shear, if the line-of-action of the load passes through the centroid of the bolt pattern, then the secondary shear force, Fi'', will be zero.

Don't attempt wrong .Downvoted for that...A flanged bolt coupling is used to connect a solid shaft 90 mm in diameter to a hollow shaft 100 mm in outsude diameter and 90 mm in inside diameter. If the allowable aring stress in the shafts and the bolts is 60 MPa, how many 10 mm diameter steel bolts must be used on a 200 mm diameter bolt circle so that the coupling will be as strong as the weaker shaft?

H.W: Design a knuckle joint for a tie rod of a circular section to sustain a maximum pull of 70 kN. The ultimate strength of the material of the rod against tearing is 420 MPa. The ultimate tensile and shearing strength of the pin material are 510 MPa and 396 MPa respectively. Determine the tie rod section and pin section. Take factor of safety = 6.

Problem 1 only, solve carefully, include the units and dra the diagram. Thanks! . A taper pin is used to fix a lever to a shaft, if it is to transmit a maximum torque of 850 in-lb. The shaft diameter is 1.75inches and has an ultimate stress of 60,000 psi, if the factor of safety is 3, findA. Force that will shear the pin, kNB. Shear pin diameter, mm

Q2/ Calculate the maximum axial stress for a 40-ft joint of 11.75-in, 60 lbm/ft, J-55 casing with short threads coupling. Where the casing is subjected to 280000 lb, axial tension load in a portion of a directional wellbore with dogleg severity of 2"/50 ft. In case of: (1)Uniform contant between the casing and the borehole wall. (2)Assuming contant between borehole wall and the casing only at the couplings,andF n+ (3)Calculate the joint setrength of the API round thread couplings.(oult = 75000 psi, wall thickness 0.489-in, Pc= 2660 psi. o yb-952000 lb, Fj-649 000 lbf).

Condition #1: A structural support for a machine is subjected to a static compression load of 20 kN. The support is manufactured from a circular rod made from SAE 1040 Hot Rolled steel. Specify suitable diameter for the cross section of the rod based on the basic size. Steel data are available in Table A-10 from the textbook. Condition #2: The same structural support of the basic size determined in Condition 1 is subjected to a tensile load of 15 kN that is repeated several thousand times over the life of the machine. This load is not an addition to the 20 kN. Specify a suitable steel that is suitable to this application based on the basic size determined in Condition #1. Loading of Condition #1 does not apply here. Condition #3: The same structural support from Condition 2 is heated from room temperature of 25°C. The support is placed inside a frame on both ends. There is a total clearance of 0.2 mm between the support and its frame. Initial length of the rod is 200 mm. Specify the…

Calculate the maximum tensile stress developed in a 1/4-20 bolt (Major dia = 0.2500" and Root dia = 0.1959"), 3" long, and a head height of 0.1875", if it is subjected to a load of 426 lbs.

The Shaft That Failed A single diameter shaft, having no steps or shoulders, drives a machine with a fairly heavy load.  The shaft rotates at 1200 rpm and extends from the bearing several times its diameter.  A vee-pulley is mounted on the shaft.  Belts drive the pulley from a motor, causing a considerable side stress.  The bearing is kept in place with a snap ring that is in a narrow groove around the shaft at the edge of the bearing.  The shaft has to be replaced several times a year at considerable cost in lost man hours and material.  Every time the shaft is severed, the millwright notices that it is at the location of the snap-ring groove.  The break has a rough crystalline surface.  Can you identify the problem and name the type of failure?  Name as many changes that could be made to correct the problem.

Draw FBD and determine Stress and Safety Factor of Bicycle Axle (Thru Axel)   Specification Weight of cyclist = 120 kg. Materials: Aluminum alloy (AL 6061-T6) Dimension: Length = 122 mm, Diameter = 12 mm, Thread pitch = 1.75 mm, Thread Length = 16 mm.