sin(3r) sin(2r) x sin(5x) (e) lim

Q: sin(2x) lim x→0 sin(7x)

A: This is infinity/infinity form, apply L-Hospital rule to proceed further.

Q: Find the limit

A: Consider the limit, First of all, apply the fraction rule, Then,

Q: sin 3x + ax + bx3 lim %3D x3

A:

Q: sin 2x Find lim x-0 3x

A:

Q: lim X-3 Sinx X-0

A: Limit of a function

Q: Lim メーラル sin2x x² 2.

A:

Q: (+) C lim x sin sin(3x) lim- 0 sin(4x) sin (x-1) lim 1 1-x+x² -x'

A:

Q: sin 2x lim x→0 2x²+x

A: the given limit is: limx→0sin2x2x2+x we have to find the value of the given limit

Q: lim x→0 (sin3x sin5x/x2)

A:

Q: Find the limit

A: We know that cos0=1  For x=0-, cosx will be less than 1.  So, |cosx-1|= -(cosx-1)= 1-cosx for x=0-…

Q: sin(7.rx) lim X-X

A:

Q: (sin 3x)(sin5x) 12. lim 7x2

A:

Q: sin x e* -e lim Solve x→0 x – sin x

A:

Q: Lim x-0 e³ +ex -x²-2 sin² x-x²

A:

Q: lim x>0 (x csc2x)/(cos5x)

A:

Q: sin3x d) lim x→0 + lim cos x + lim 2x² x→2 x-3

A:

Q: sin(3 – x) lim с2 — 5х + 6 x→2 x2 – 5x + 6

A:

Q: lim sin (–3 x z) = z-3

A: To find- the limit.

Q: lim x→0 (sin 4x/ sin 6x)

A:

Q: Lim 2-2 cosx - xIn (1+x). x sin'x

A: We apply L hospital rule to find the limt. See 2nd,3rd and 4th step.

Q: sin(3 – x) lim x→1 x2 – 5x + 6

A: Explained below

Q: lim 1-e*) X-0 x sin x

A:

Q: sin 14x lim x-0 sin 7x 3x (7x – 2) lim x+0 \7x + 3.

A: limx→0sin14xsin7xAs we know that if limx→a-f(x)=limx→a+f(x)=Llimx→0sin(14x)sin(7x)=00This is…

Q: sin(3x – 3) lim x² – 1

A: Given :

Q: sin(x ²–4) -4) lim x+2) tan (x+2) x→-2

A: Rearrange the expression than Apply the limit and simplify.

Q: lim (-4 0 sin x x

A: Let ,I=limx→ 01sinx-1xTaking cross multilplicationI=limx→ 0x-sinxxsinxI=0-sin(0)0sin(0)I=00Which is…

Q: lim 15 cos() x→0+ 7x

A:

Q: Evaluate the limit.

A: To evaluatelimx→0sin5xsin2xsin3xsin5x

Q: lim x → 0 sin^8 x / x

A:

Q: sin (-11x) lim x→0 _tan(9x)

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: sin(3x) 6)lim x→0 sin(4x)

A: We have to evaluate the value of limx → 0 {sin(3x)/sin(4x)}

Q: (sin(2x)+7x2-2х 3. lim x→0 х4+2х3+x2

A:

Q: Find the limit

A: Given limit is Dividing both numerator and denominator by x, we get

Q: sin3 (x) Find lim х30 х-хсos(4x)

A: To evaluate the given limit.

Q: sin 4x 18) lim X-0 tan 5x

A:

Q: 4.x (a) lim 10 sin 5x sin() (b) lim 5x sin 3x (c) lim 10 x2 tan 2.x

A: Read the following instructions once 1. Short method is provided at the end of the subpart (c)…

Q: sin-1(e* 2 lim V1 - e2x x→0-

A:

Q: sin6x lim 0 X sin2x

A:

Q: Lim e^x +e^-x-x²-2/sin²x-x² when x approaches 0

A: The given limit is, This limit is in 0/0 form, so we can apply L’Hospital's rule,

Q: sin(3) (x – 6) – 3sin(x – 6) lim x-6 (x – 6)2 + 2(x – 6) + 3 – 3e*-6

A: We have to find the limit.

Q: sin (1 cos x) sin x -0" sin Vx sin (x2 + x) 25. lim 26. lim sin (sin x) 27. lim 28. lim sin (x - 4)…

A:

Q: +lim x-0 e -x - 8x ex - e x - sin x

A:

Q: lim x (1 – cos X→-0

A: limx→-∞x1-cos1x

Q: sin(3 – x) lim x→3 x² - 5x + 6

A:

Q: lim cos(x) X- +x 3 TC 2.

A:

Q: sin 2x B) Find: limx→0 2x2+ x

A:

Q: sin(4.x) Find lim 1-0 tan(2x)

A:

Q: sin 5x 17) lim х-0 sin x

A: