since the space lattice system is in balance OBD determine the forces acting on the bar
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- The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontalThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.2. The homogeneous bar AB weighs 25 lb. Determine the forces acting on the bar at A and B. Neglect friction. 60° A
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=250 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is γ=6°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=40°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseAs shown by this image, the chandelier is supported by several ropes and is in equilibrium. Cable BC is horizontal. If angle theta is 31 degrees. and the ropes are of the same type and will fail if the tension force reaches 410lb, determine the maximum weight in lb) the chandelier can have without making any of the ropes break.
- ck C rests on the uniform 15-lb bar AB. The cable conne ey at D. Find the magnitude of the force acting between t 30 -2 ft+ -6 ft- C.Q2 The 80-lb block C rests on the uniform 15-lb bar AB. The cable connecting C to B passes over a pulley at D. Find the magnitude of the force acting between the block and the bar. C. 30The collar C is fixed to rod AB using a glued bond that allows a maximum force of 405 N parallel to the axis of the rod. The collar has weight W acting in the negative z direction. Determine the weight W in N of the collar that will cause the glued bond to break as shown in figure.
- Q1. Find the centroid 200 mm 200 mm 400 mm Q2. Find Ien 30- 50 20 A 40 R= 20 +20 +40- + 20 - Q3. Determine the force in members CE, DE, and DF. 1 kN 2 kN 2 kN 2 kN 1 kN H 0.4m F D | B. 2 m C E G 2.4 m 2.4 m 2.4 m 2.4 m 2/2600 lb 2.5 ft 2.5 ft 2.5 t 2.5 ft E 1. The structure is: 2. The two-force member is: AB and CD v and its 3. Given that Fx +1000 Ib and Fy =+1000 Ib (Hint: take the moments at B), the magnitude of internal force FCD is:The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is given as γ=8°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=50°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N)b) Find the tensile force T2 in cable 2. (Write your result in N)c) Find the angle α of cable 1 with the horizontal.