solid sphere of radius a is centered at the origin. It is made of an insulating material and carries a uniform charge density with total charge Q1. It is surrounded by a hollow, concentric conducting shell of inner radius b and outer radius c. The outer shell has total charge Q2. Q1 = +10 µC Q,-5 μC What is the magnitude of the electric Q2 %3D field at the point x = 30 cm on the x-axis? a = 5 cm b = 15 cm Q1 C = 20 cm b What is the potential difference V(r) – V(0) for r

Physics for Scientists and Engineers
10th Edition
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Author:Raymond A. Serway, John W. Jewett
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Chapter23: Continuous Charge Distributions And Gauss's Law
Section: Chapter Questions
Problem 32P: Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure...
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solid sphere of radius a is centered at the origin. It is made of an insulating material and carries a uniform
charge density with total charge Q1. It is surrounded by a hollow, concentric conducting shell of inner radius b and outer
radius c. The outer shell has total charge Q2.
y
Q1 = +10 µC
Q2 = -5 µC
a = 5 cm
b = 15 cm
What is the magnitude of the electric
Q2
field at the point x = 30 cm on the x-axis?
Q1
C = 20 cm
b
What is the potential difference V(r) – V(0) for r<a (i.e., where r is inside the insulating sphere, and V(0) is
the potential at the origin)?
kQır²
a. V (r) – V (0)
2a3
kQır?
2а3
kQ2
b. V (г) — V (0) %3
kQır2_ kQ2
c. V (r) – V (0) =
2a3
kQır
d. V (r) – V (0)
2a2
e. V (r) – V (0) = 0
Calculate the total charge on the outer surface of the conducting shell at r = c = 20 cm.
Transcribed Image Text:solid sphere of radius a is centered at the origin. It is made of an insulating material and carries a uniform charge density with total charge Q1. It is surrounded by a hollow, concentric conducting shell of inner radius b and outer radius c. The outer shell has total charge Q2. y Q1 = +10 µC Q2 = -5 µC a = 5 cm b = 15 cm What is the magnitude of the electric Q2 field at the point x = 30 cm on the x-axis? Q1 C = 20 cm b What is the potential difference V(r) – V(0) for r<a (i.e., where r is inside the insulating sphere, and V(0) is the potential at the origin)? kQır² a. V (r) – V (0) 2a3 kQır? 2а3 kQ2 b. V (г) — V (0) %3 kQır2_ kQ2 c. V (r) – V (0) = 2a3 kQır d. V (r) – V (0) 2a2 e. V (r) – V (0) = 0 Calculate the total charge on the outer surface of the conducting shell at r = c = 20 cm.
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