Suppose a list is (2, 9, 5, 4, 8, 1). After the first pass of bubble sort, the list becomes O2, 9, 5, 4, 8, 1 2, 9, 5, 4, 1, 8 O2, 5, 9, 4, 8, 1 2, 5, 4, 8, 1,9 2, 1, 5, 4, 8, 9
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- Programming language : Java Write the program the should determine if there exists a 3 partition of the given list, P1, P2, and P3 such that the sum of the elements in P1 minus the sum of the elements in P2 are exactly k and the sum of the elements in P2 minus the sum of the elements in P3 are also exactly k. k is a positive integer, or zero. P1, P2, and P3 are the partitions such that |sum(P1) - sum(P2)| = k and |sum(P2) - sum(P3)| = k. For example if list is given below: 1. List = [3 1 3 2 1] k = 4 Output: True The 3 partition form above list which satifies the condition is: P1 = {2}, P2 = {3, 3}, P3 = {1, 1} Sum(P1) = 2 Sum(P2) = 6 Sum(P3) = 1 + 1 = 2 |Sum(P1) - Sum(P2)| = 4 |Sum(P2) - Sum(P3)| = 4 2. List = [49 49 36 44 43 49 48 36 32 26 38] k = 88 Output: True A 3 partition that works is…JAVA CODE PLEASE Linked List Practice l by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes then print the five nodes using the printNodes function. An initial code is provided for you. Just fill in the blanks. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5Q1. Write the following method that returns thesmallest element in an ArrayList:public static <E extends Comparable<E>> E min(ArrayList<E> list).
- 5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexListP5:Given the following singly linked list: s->m->h->t->y->h->r If you run the following function, then print out the linked list, what do you get? void SLL::f3() ( SNode *tmp; SNode *tmp2 - first; // holds the address of "s" while (tmp2->next !- NULL) { tmp = tmp2->next; tmp2->next = tmp2->next->next; tmp->next = first; first = tmp; last = tmp2;JAVA CODE PLEASE Linked List Practice ll by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes. Arrange the nodes in ascending order first before printing them using the printNodes function. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5
- def sort and_pop(x: list, i: int) -> list: x.sort() return x.pop(i) # Dan's code lst = [23, 17, 3, 13, 11, 5, 7, 2, 19, 1] lst = sort_and_pop(lst, 5) lst = sort_and_pop(lst, 2) II I| || If you run this code, you'll find that it produces an error. Surprise! According to the type contract, Dan's Code should work. But it doesn't, because the function type contract has faulty type annotations. Correct the function type contract so that it's clear from the type contract that Dan's code will not work. (Dan's Code will and should remain an incorrect use of the function!) TODO: Write a new type contract"" "An element that comprises more than half of the items in an array is referred to as a majority element. Find the dominant element in a list of positive integers. Return -1 if there is no majority element. Execute this in 0(1) space and O(N) time.Input: 1 2 5 9 5 9 5 5 55 outputAn element that comprises more than half of the items in an array is referred to as a majority element. Find the dominant element in a list of positive integers. Return -1 if there is no majority element. Execute this in 0(1) space and O(N) time.Input: 1 2 5 9 5 9 5 5 55 outputGiven the following linked lists: Trace the following codeon these two linked lists and show what will be printed.
- Write the following function that sorts and merges two lists into a new sorted list. The new list contains only even numbers. def myMergeEvenList(list1, list2): Enter list1: 10,5,6,7 Enter list2: 12,8,5,0,1 The merged list is: 0,6,8,10,12The code below is for: 1. Create a sorted linked list using tenStudent array (copy from array into the linked list will be done). 2. Append an element to the end of a list 3. Delete the last element from a list. 4. Delete the nth element from a list. >>>>>>>>>>> I need to complete the code to do : a. Using the linked list which is populated at step 1, create a binary tree. The new tree will be created during the deletion of the linked list. b. Print the content of the tree using “Inorder traversal”. c. Concatenate two lists The rest of question details in picture.. thank you The code: #include<stdio.h>#include<stdlib.h> struct student{int TC;char F_name[12];char L_name[12];int age;char gender[2];};struct student tenStudent[10] = {123,"X1","Y1",21,"M",234,"X2","Y2",26,"F",128,"X3","Y3",18,"M",432,"X4","Y4",27,"M",287,"X5","Y5",34,"F",423,"X6","Y6",21,"M",634,"X7","Y7",16,"F",828,"X8","Y8",15,"M",252,"X9","Y9",27,"F",887,"X10","Y10",34,"F",};…def remove_occurences[T](xs:List[T], elem: T, n:Int) : List[A] = {} Using the function above, can you show me how to make a polymorphic function in scala where the program removes elem , n number of times from the list. If n > elem then remove all elem from the list For example: remove_occurences(List(4,5,6,7,4),4,1) -> List(5,6,7,4)remove_occurences(List(4,5,6,7,4),4,2) -> List(5,6,7)remove_occurences(List(4,5,6,7,4),2,2) -> List(4,5,6,7,4)