t charts that illustrate the execution of these processes using the following scheduling algorithms and calculate the average waiting time. Round-Robin (RR) with Time quantum = 4
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Draw Gantt charts that illustrate the execution of these processes using the
following scheduling
- Round-Robin (RR) with Time quantum = 4
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- Consider the following set of processes, the length of the CPU burst time given in milliseconds: Process Burst Time P1 6 P2 8 P2 7 P4 3 Assuming the above processes are being scheduled with the Shortest Job First (SJF) scheduling algorithm. The waiting time for process P1 is 3ms The waiting time for process P1 is 0ms The waiting time for process P1 is 16ms The waiting time for process P1 is 9ms From the following list which is the deadlock avoidance algorithm? Banker’s algorithm Round-robin algorithm Elevator algorithm Karn’s algorithm A problem encountered in multitasking when a process is perpetually denied necessary resources is called Deadlock Starvation Inversion Aging To break a deadlock: Abort one or more processes to break the circular wait Abort all the process in the system Preempt all resources from all processes None of the mentioned Termination of the process terminates First thread of the process First two threads…Given the list of processes, their CPU burst times, arrival times and priorities implement SJF,Priority and Round Robin scheduling algorithms on the processes with preemption. For each ofthe scheduling policies, compute and print the completion Time(CT), Turnaround Time(TAT),and Waiting Time(WT) for each process using C Programming.Waiting time: Processes need to wait in the process queue before execution starts and inexecution while they get preempted. Turnaround time: Time elapsed by each process to get completely served. (Difference betweensubmission time and completion time).Consider the following set of processes, the length of the CPU burst time given in milliseconds: Process Burst time: P1 6 P2 8 P3 7 P4 3 Assuming the above process being scheduled with the SJF scheduling algorithm: The waiting time for process P1 is 3ms. The waiting time for process P1 is 0ms. The waiting time for process P1 is 16ms. The waiting time for process P1 is 9ms.
- Consider the following set of processes, with the length of the CPU-burst time given in milliseconds, Process CPU Burst Time P1 P2 1 P3 P4 1 P5 7 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5 all at time 0. Draw four Gantt charts illustrating the (i) execution of these processes using SJF and RR (quantum = 1) scheduling. (ii) What is the waiting time of each process for each of the scheduling algorithms in part (i)? %3DConsider the following set of processes, with the length of the CPU burst given in milliseconds. Process Burst Time Priority P1 2 2 P2 1 1 P3 8 4 The processes are assumed to have arrived in the order of P1, P2, P3, P4, P5 all at time 0. a. Draw the Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: preemptive priority (a larger priority number implies a higher priority), and RR (quantum = 2). b. What is the turnaround time of each process for each of the scheduling algorithms in part i? c. Which of the algorithms results in the minimum average waiting time (over all processes)?Consider the following set of processes, with the length of the CPU burst given in milliseconds: Process Burst Time Priority P1 2 2 P2 1 1 P3 8 4 P4 4 2 P5 5 3 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. Draw four Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, SJF, non-preemptive priority (a larger priority number implies a higher priority), and RR (quantum = 2). What is the turnaround time of each process for each of the scheduling algorithms in part a? What is the waiting time of each process for each of these scheduling algorithms? Which of the algorithms results in the minimum average waiting time (over all processes)?
- Consider the following set of processes, with the length of the CPU burst time given in milliseconds: Process Burst Time Priority P1 1 3 P2 3 1 P3 2 5 P4 4 4 P5 5 2 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. Draw 2 Gantt charts that illustrate the execution of these processes using the following 2 scheduling algorithms: non-preemptive priority (a smaller priority number implies a higher priority), and RR (quantum = 1). What is the turnaround time of each process for each of the scheduling algorithms in part a? Explain why What is the waiting time of each process for each of these scheduling algorithms?Explain whyConsider the following set of processes, with the length of the CPU burst given in milliseconds: Process Burst Time Priority P1 2 2 P2 1 1 P3 8 4 P4 4 2 P5 5 3 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. Draw four Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, SJF, nonpreemptive priority (a larger priority number implies a higher priority), and RR (quantum = 2). What is the turnaroundConsider the following set of processes, with the length of the CPU bursts given in milliseconds. The processes are assumed to have arrived in the order P1, P2, P3, P4, P5 all at time 0 Process Burst Time Priority P1 5 3 P2 11 4 P3 12 P4 1 P5 7 2 a. Draw 3 Gantt charts that illustrate the execution of these processes using the following schedulin algorithms. i. FCFS. Non pre-emptive priority with arrival time for P1, P2, P3, P4 and P5 as 0,2,3,4,5 respectively. (A smaller priority number implies a higher priority). SJF with arrival time for P1, P2, P3, P4 and P5 as 1, 2, 3, 4, 5. ii. 292 iii. b. Calculate the average waiting time for FCFS and SJF scheduling algorithms mentioned in the previous question. Show your work?
- Let the processes P1, P2, P3, and P4 be given. They arrive in the system at the same time in this order. The processes have the following service times (in time units): Process P1 P2 P3 P4 Service time (CPU burst) 53 17 68 24 For the scheduling method "Round Robin" (RR), specify the average execution time (average turnaround time) and the number of context switches. The time quantum q is set to 20 time units. You must show your calculations. You will not have to draw Gantt charts. Note: For RR, processes execute in order of their ID (i.e., P1-P2-P3-P4).The following processes are being scheduled using a preemptive, roundrobin scheduling algorithm. Each process is assigned a numericalpriority, with a higher number indicating a higher relative priority.In addition to the processes listed below, the system also has an idle task (which consumes no CPU resources and is identified as Pidle). Thistask has priority 0 and is scheduled whenever the system has no otheravailable processes to run. The length of a time quantum is 10 units.If a process is preempted by a higher-priority process, the preemptedprocess is placed at the end of the queue.Consider the following set of processes, with the length of the CPU-burst time given in milliseconds, Process CPU Burst Time P1 P2 1 P3 3 P4 1 P5 7 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5 all at time 0. (i) Draw four Gantt charts illustrating the execution of these processes using SJF and RR (quantum = 1) scheduling. %3D 5