Table 2. 5 shows the amount, in inches, of annual rainfall in a sample of towns. Table 2.5: Rainfall (Inches) Frequency Relative Frequency Cumulative Relative Frequency 2.95-4.97 * = 0.12 0.12 4.97-6.99 7 = 0.14 0.12+ 0.14 = 0.26 6.99-9.01 15 0.30 0.26 + 0.30 = 0.56 %3D 9.01–11.03 8 = 0.16 0.56+ 0.16 = 0.72 11.03–13.05 = 0.18 0.72 + 0.18 = 0.90 13.05–15.07 5 = 0.10 0.90 + 0.10 = 1.00 %3D Total = 50 Total = 1.00

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.1: Stem-and-leaf Plots And Histograms
Problem 2E
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1. Find the percentage of rainfall that is less than 9.01 inches.

Table 2. 5 shows the amount, in inches, of annual rainfall in a sample of towns.
Table 2.5:
Rainfall (Inches)
Frequency
Relative Frequency
Cumulative Relative Frequency
2.95-4.97
= 0.12
50
0.12
4.97-6.99
7
0.14
50
0.12 + 0.14 = 0.26
15 = 0,30
50
0.26+ 0.30 = 0.56
6.99-9.01
15
9.01-11.03
8
= 0.16
0.56+0.16 = 0.72
%3D
11.03–13.05
9
= 0.18
0.72 + 0.18 = 0.90
%3D
13.05–15.07
5
= 0.10
0.90+0.10 = 1.00
%3D
50
Total = 50
Total = 1.00
Transcribed Image Text:Table 2. 5 shows the amount, in inches, of annual rainfall in a sample of towns. Table 2.5: Rainfall (Inches) Frequency Relative Frequency Cumulative Relative Frequency 2.95-4.97 = 0.12 50 0.12 4.97-6.99 7 0.14 50 0.12 + 0.14 = 0.26 15 = 0,30 50 0.26+ 0.30 = 0.56 6.99-9.01 15 9.01-11.03 8 = 0.16 0.56+0.16 = 0.72 %3D 11.03–13.05 9 = 0.18 0.72 + 0.18 = 0.90 %3D 13.05–15.07 5 = 0.10 0.90+0.10 = 1.00 %3D 50 Total = 50 Total = 1.00
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