Task 06: Use the recursive definition of Fibonacci series and write a function int fib(int n) that returns Fn (nth element of Fibonacci series). For example, if n 0, then fib() should return 0. If n = 1, then it should return 1. For n> 1, it should return Fn-1 + Fn-2 hint: If n is 8, the function should return 21 (that is 8th element in sequence below). 0, 1, i, 2, 3, 5, 8, 13, 21, 34
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- Recursive Sum! Write a recursive function rc_sum(n:int) -> int that returns the sum of the first n positive integers. The function should look very similar to the factorial function you have seen before. Your Answer: 1 # Put your answer here 2 Submit1. Write a recursive method expFive(n) to compute y=5^n. For instance, if n is 0, y is 1. If n is 3, then y is 125. If n is 4, then y is 625. The recursive method cannot have loops. Then write a testing program to call the recursive method. If you run your program, the results should look like this: > run RecExpTest Enter a number: 3 125 >run RecExpTest Enter a number: 3125 2. For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Once m is 0, the function returns n. Once n is 0, the function returns m. If neither is 0, the function can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n. Although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. Meaning your code needs to follow the given algorithm. Then…Fibonacci numbers are a sequence of integers, starting with 1, where the value of each number is the sum of the two previous numbers, e.g. 1, 1, 2, 3, 5, 8, etc. Write a function called fibonacci that takes a parameter, n, which contains an integer value, and have it return the nth Fibonacci number. (There are two ways to do this: one with recursion, and one without.)
- Digital Sum The digital sum of a number n is the sum of its digits. Write a recursive function digitalSum(n:int) -> int that takes a positive integer n and returns its digital sum. For example, digitalSum (2019) should return 12 because 2+0+1+9=12. Your Answer: 1 # Put your answer here 2 SubmitCodeW X b For func x C Solved X b Answer X https://codeworkou... CodeWorkout X270: Recursion Programming Exercise: Count Characters For function countChr() write the missing part of the recursive call. This function should return the number of times that the letter "A" appears in string "str". Recall that str.substring(a) will return the substring of str from position a to the end of str, while str.substring (a, b) will return the substring of str starting at position a and continuing to (but not including) the character at position b. Examples: countChr ("ctcoWCAt") -> 1 Your AnsSwer: 1 public int countChr(String str) { 2. if (str.length() return 0; } (0 4. { int count = 0; www. 5. 9. if (str.substring(0, 1).equals("A")) { count = 1 7. { 9. return count + > 1:10 AM 50°F Clear 12/4/2021 呼Write a recursive function that displays a string reversely on the console using the following header: def reverseDisplay(value):For example, reverseDisplay("abcd") displays dcba. Write a test programthat prompts the user to enter a string and displays its reversal.
- Write a function that takes in an integer n and computes n!. Do this without recursion. In [ ]: deffactorial_iter(n):"""Takes in an integer n>0 and returns the product of all integers from 1 to n."""# YOUR CODE HEREraiseNotImplementedError() In [ ]: In [ ]: assert factorial_iter(6) == 720 assert factorial_iter(7) == 5040 assert factorial_iter(10) == 3628800CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Write a recursive function that displays a string reversely on the console using the following header: void reverseDisplay(const string& s) For example, reverseDisplay("abcd") displays dcba. Write a test program that prompts the user to enter a string and displays its reversal.
- Write a recursive function that takes as a parameter a nonnegative integer and generates the following pattern of stars. If the nonnegative integer is 4, the pattern generated is as follows: **** *** ** * * ** *** **** Also, write a program that prompts the user to enter the number of lines in the pattern and uses the recursive function to generate the pattern. For example, specifying 4 as the number of lines generates the preceding pattern.Write a recursive function that takes as a parameter a nonnegative integer and generates the following pattern of stars. If the nonnegative integer is 4, then the pattern generated is:********************Also, write a program that prompts the user to enter the number of lines in the pattern and uses the recursive function to generate the pattern. For example, specifying 4 as the number of lines generates the above pattern.Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is my original code that needs to be fixed: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. if nameList == len(permList) - 1: return nameList else: for x in range(permList, len(nameList)): permList[nameList], permList[x] = permList[x], permList[name_List] return all_permutations(permList, nameList + 1) permList[nameList], permList[x] = permList[x], permList[name_List] if __name__ == "main": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)