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- 7. Use the set-roster notation to indicate the elements in eachof the following sets.a. V = {s ∈ Z| s > 2 or s < 3}b. W = {t ∈ Z | 1 < t < −3}c. X = {u ∈ Z | u ≤ 4 or u ≥ 1}HW 2: Given the regular expression a*(a/b)aa: • Construct an equivalent NFA using Thompson's construction. • Convert this NFA to a DFA using the subset construction method.A BST is constructed in the usual way using the node definition below. Write a function int child2( bst node t *curr) that returns the number of nodes that have 2 children. typedef struct BST NODE T {int data;struct BST NODE T *left, *right; } bst node t; int child2( bst node t *curr){ }
- typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)Genere Program Contexts for given statement: If a node n is traversed that corresponds to the pre-header node of a loop L, then function init prehender(n) is invoked which initializes the recurrence variables of L in context c_{b}(n) with the value of u.the folding operator (c, c1, c2 and cs are contexts)Relational Thinking sets 25 students attend a programming workshop. 15 students study Python. 14 students study Java. 5 students changed to another field of study. How many students study both Java and Python. Use set diagrams to explain your answer. Draw the diagram showing the relationship A ⊆ B Draw the diagram to show the relationship A ∩ B Let E be the set of even numbers, and let P be the set of prime numbers. Use set notation to express the following statement: “2 is the only even prime number.” List the set operations most closely matching disjunction, conjunction, negation, conditional (if then), biconditional (iff if and only if)
- Course: Data Structure and Algorithms Language: C++ Question is well explained Question #2Implement a class for Circular Doubly Linked List (with a dummy header node) which stores integers in unsorted order. Your class definitions should look like as shown below: class CDLinkedList;class DNode {friend class CDLinkedList;private int data;private DNode next;private DNode prev;};class CDLinkedList {private:DNode head; // Dummy header nodepublic CDLinkedList(); // Default constructorpublic bool insert (int val); public bool removeSecondLastValue (); public void findMiddleValue(); public void display(); };Topic: Doubly Linked List Deque Implement the following problem in the main case 0 (see attached photo) Your algorithm for the hierarchy problem should follow this: Evaluate the final set of operations first given the set of rules. Then, do the remove operations. Finally, do the add operations. DO NOT MIND THE #include "dlldeque.h" it is already implemented only the case 0 needs to be solved #include <iostream> #include <cstring> #include "dlldeque.h" using namespace std; int main(int argc, char** argv) { DLLDeque* deque = new DLLDeque(); int test; cin >> test; switch (test) { case 0: // perform your Hierarchy implementation here // utilize the deque initialized, // initialize variables you need before switch // you can use the print() method to debug, but not the final_print() // do not modify from this point onwards deque->final_print();…3. The class definition for sparse matrix is shown below. struct Triple{int row, col, value;};class Matrix; // forward declarationclass MatrixNode{friend class Matrix;friend istream& operator>>(istream&, Matrix&); // for reading in a matrixprivate:MatrixNode *down, *right;bool head; // a head node or notunion{ // anonymous unionMatrixNode *next;Triple triple;};MatrixNode(bool, Triple*); // constructor};MatrixNode::MatrixNode(bool b, Triple *t) // constructor{head = b;if (b){right = down = this; // row/column header node}elsetriple = *t; // element node or header node for list of header nodes}class Matrix{friend istream& operator>>(istream&, Matrix&);public:~Matrix(); // destructorprivate:MatrixNode *headnode;}; Based on this class, do the following tasks. Write the C++ function, operator+(const Matrix& b) const, which returns the matrix *this + b. Write the C++ function, operator*(const Matrix& b) const, which returns the matrix *this *…
- Question 20 A list is a collection with additional index- and iteration- related operations. True False Question 21 O(N) is the order of growth execution time of the size operation when using the SortedArrayCollection class, assuming a collection size of N. True False Question 22 If N represents the number of elements in the list, then the index-based set method of the ABList class is O(1). True False Question 23 O(N) is the order of growth execution time of the remove operation when using the LinkedCollection class, assuming a collection size of N. True False Question 24 It is not possible to use an array to implement a linked list. True False Question 25 O(N) is the order of growth execution time of the remove operation when using the ArrayCollection class, assuming a collection size of N. True False Question 26 Our linked implementation of lists implements a bounded list. True False Question 27 O(N) is the order of growth execution time of the contains operation…Look at the two functions Merge-and-Count & Sort-and-Count. You are also given an array- Awesome_Array= 3 7 10 14 18 19 2 11 Merge-and-Count (A, B){ curA = 0; curB = 0; count = 0; mergedList = empty list while (not at end of A && not at end of B){ a = A[curA]; b = B[curB]; if (a < b) append a to mergedList; curA++; else append b to mergedList; curB++; count = count + number of elements left in A } if (at end of A) append rest of B to mergedList; else append rest of A to mergedList; return (count, mergedList); } Sort-and-Count(L){ if list L has one element return (0, L) Divide the list into two halves A and B (rA, A) ← Sort-and-Count(A) (rB, B) ← Sort-and-Count(B) (rC, L) ← Merge-and-Count(A, B) total_count =…Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)