Task 1: Write the truth table for both full and half adders as well as the simplified equations. (Show your work for simplifying the equations). Use XOR or XNORS where appropriate. Half Adder S= C= Full Adder S= C= A B 0 0 0 1 1 0 1 1 Half Adder C 0 0 0 OL 0 Full Adder A B SC 0 0 1 0 1 0 0 1 COO 0 LLO 1 1 SC 1 1 0
Q: control systems
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- What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.1.2 Convert to octal. Convert to hexadecimal. Then convert both of your answers to decimal, and verify that they are the same. 111010110001.011, (b) 10110011101.112processors Systems And Interfacing If you subtract two decimal numbers, after BCD subtraction, to correct the result we use Oa AAA Instruction Ob AAM instruction Oc DAA instruction Od. DAS instruction Next page Windows bu alacy Jait ------ hp f3 ア D f7 19 %23 & フ R T Y Y ! VACO 12 DI F 1 G Y BY N T こo つ
- What will be the modified form of the following codeword is odd parity scheme is used: Codeword: 0110101A system uses two-dimensional parity. Find the parity unit for the following three data units: 00110 11001 00001. Assume even parity. (write down the sequence of 0's and 1's without any blank space). hints: answer is 6 bitDescribe each of the following expressions as SOP/POS. Discuss the no. of variables and identify min term (standard product term) or max term (standard sum term) F = A BC'D + AB + B`CD + D` * SOP POS min term = A`BC`D max term %3D max term = A`BC`D Number of variables Number of variables = 4
- Q1. Convert following numbers in given radix system: a. (697)10 into Octal and Hexa decimal b. (2D9)16 into Decimal and Octal Q2. Using two's complement representation, solve: a. 101110001 – 1111111001 b. 1010101010 – 1010010101 Q3. Perform following arithmetic operations: a. (6767)10 + (3592)10 using BCD b. (C7C)16 - (B0E)16 using 16's complement Q4. A code 1011011 needs to be sent to the receiver. Using, hamming code find out the code- word and the mechanism to check the corrected data when error occurred at 4th bit. (Assumptions: Right to Left with Odd Parity) Q5. (a) Convert the following logic gate circuit into a Boolean expression, writing Boolean sub-expressions next to each gate output in the diagram: A (b) Realise Ex-OR gate using universal gate? Q6. Implement and simplify f (A, B, C, D) = E(1,3,5,8,9,11,13,15) using K-map?For each of the problems, fill in the missing number or operator to make the equation true. (show help) e110 e010 0000 1111 e011 e100 e011 1001 e011 e000 0001 ee10 0101 1100 e101 elee >> e01e e1e0 ee0e e010 e00e e011 • 0010 0000 0011 0001 000e 0100 e11e e100 e111 1100 e011 1100 011e 0011 e11e e101 e101 1001 « 0000 0010 | 0010 0011 ee1e 1110 e100 1101 >> • 0101 1101 1111 0000 e0ce e110 011e 1111 e100 1100 0010 e111 0100 1110 0011 0110 0111 e001 0100 1000 ee01 1110 & 0101 0010 0110 e111 e000 1010 e110 1110 0110 0000 . 0001 e11e 0100 0010 011e 1110 e111 1100 e011 0101 eee1 e11e e100 e001 e001 1000 » e000 0011 » 000e e010 e010 0111 e111 0001 0101 1100 0111 0111 0111 1001 e11e 1011 0010 e000 e011 1011 e110 e110 e101 1110 e001 1e01 & 0100 e101 « 0000 001e & e00e e010 0010 0111 e00e 1000 0110 0100 0001 0111 e011 1111 0100 e111 e111 1011 e010 1010 e011 0000 e000 1101 e111 101e « e00e e011 0111 1110 ee0e e011 e00e e010 0011 1111 0101 1000 • 0000 0001 1110 1000 e01e e001 e001 1100 0110 0111 ee01…Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C
- A. Use Microsoft Visual Basic to design a form contain two text boxes and one button called "add", and after click on "add", we get the summation of the numbers between (10 -30), and display the result on text box1 and get the summation of the numbers between (60-80) and display the result on text box2.3 For each of the following Boolean expression, do the followings: 3.1 H = AB + B a. Draw the electrical schematic diagram using IEC standardized referencing, symbol and terminal numbering. b. Describe the operation of the circuit 3.2 L = AB + AC + ABC a. Draw the electrical schematic diagram using IEC standardized referencing, symbol and terminal numbering. a. Describe the operation of the circuit 目7. Add the following binary mumbers: 10010 1011101 10011 +1100 + 1000000 + 1111101 10011001 11000011 1001100 100111 + 101111 + 1100101