Temperature Participant 40 Degrees 60 Degrees 80 Degrees Participant Totals A 3.22 3.42 3.46 P = 10.10 n 5 B 3.27 3.31 3.35 P = 9.93 k = 3 C ດ 3.47 3.93 3.69 P = 11.09 N = 15 D 3.43 3.91 3.74 P = 11.08 G 53.53 E 3.35 4.16 3.82 P = 11.33 ΣΧ = 192.1709 T = 16.74 SS = 0.0441 T = 18.73 SS = 0.5286 T = 18.06 SS 0.1575 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.) ANOVA Table Source SS df MS F Between treatments Within treatments Between subjects 0.0609 0.1372 Error Within treatments Between subjects Error Total F Distribution Numerator Degrees of Freedom = 26 Denominator Degrees of Freedom = 26 kkkk 14 .5000 .5000 0.0609 0.1372 0 1 1.00 2 3 4 5 6 7 00 8 Use the Distributions tool to find the critical value for a = 0.01. The critical value is F = At a significance level of a = You 9 F 0.01, evaluate the null hypothesis that the population means for all treatments are equal. The null hypothesis is conclude that temperature affects spatial reasoning abilities.
Temperature Participant 40 Degrees 60 Degrees 80 Degrees Participant Totals A 3.22 3.42 3.46 P = 10.10 n 5 B 3.27 3.31 3.35 P = 9.93 k = 3 C ດ 3.47 3.93 3.69 P = 11.09 N = 15 D 3.43 3.91 3.74 P = 11.08 G 53.53 E 3.35 4.16 3.82 P = 11.33 ΣΧ = 192.1709 T = 16.74 SS = 0.0441 T = 18.73 SS = 0.5286 T = 18.06 SS 0.1575 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.) ANOVA Table Source SS df MS F Between treatments Within treatments Between subjects 0.0609 0.1372 Error Within treatments Between subjects Error Total F Distribution Numerator Degrees of Freedom = 26 Denominator Degrees of Freedom = 26 kkkk 14 .5000 .5000 0.0609 0.1372 0 1 1.00 2 3 4 5 6 7 00 8 Use the Distributions tool to find the critical value for a = 0.01. The critical value is F = At a significance level of a = You 9 F 0.01, evaluate the null hypothesis that the population means for all treatments are equal. The null hypothesis is conclude that temperature affects spatial reasoning abilities.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter1: Variables, Expressions, And Integers
Section1.5: Adding Integers
Problem 45E
Related questions
Question
PLease help me solve the following question, explain and make sure is 1000%% correct thanks !!
Transcribed Image Text:Temperature
Participant
40 Degrees
60 Degrees 80 Degrees
Participant Totals
A
3.22
3.42
3.46
P = 10.10
n
5
B
3.27
3.31
3.35
P = 9.93
k
=
3
C
ດ
3.47
3.93
3.69
P = 11.09
N
=
15
D
3.43
3.91
3.74
P = 11.08
G
53.53
E
3.35
4.16
3.82
P = 11.33
ΣΧ =
192.1709
T = 16.74
SS = 0.0441
T = 18.73
SS = 0.5286
T = 18.06
SS 0.1575
The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means
are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the
missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the
order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your
answers and the answer choices.)
ANOVA Table
Source
SS
df
MS
F
Between treatments
Within treatments
Between subjects
0.0609
0.1372
Error
Transcribed Image Text:Within treatments
Between subjects
Error
Total
F Distribution
Numerator Degrees of Freedom = 26
Denominator Degrees of Freedom = 26
kkkk
14
.5000
.5000
0.0609
0.1372
0
1
1.00
2
3
4
5
6
7
00
8
Use the Distributions tool to find the critical value for a = 0.01. The critical value is F =
At a significance level of a =
You
9
F
0.01, evaluate the null hypothesis that the population means for all treatments are equal. The null hypothesis is
conclude that temperature affects spatial reasoning abilities.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images
Recommended textbooks for you
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage