Determine the applied load P needed to cause theta = 44.6° The A-36 steel wire AB has a cross-sectional area of 11 mm2 and is unstretched when0 = 45.0° (Figure 1)Figure400 mmA0400 mmBYP<1 of 1>

The A-36 steel wire AB has a cross-sectional area (A) of 11 mm² and is unstretched when thita…

Answered: The A-36 steel wire AB has a…

The A-36 steel wire AB has a cross-sectional area of 11 mm² and is unstretched when 0= = 45.0°.(Figure 1) Figure 400 mm A 0 400 mm B P 1 of 1

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.2.15P: Repeat Problem 11.2-14 using L = 12 ft, ß = 0.25 kips/in., ßRl= 1.5ßL2, and ßR2= 2 ßR1.

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Question

Determine the applied load P needed to cause theta = 44.6°

The A-36 steel wire AB has a cross-sectional area of 11 mm2 and is unstretched when
0 = 45.0° (Figure 1)
Figure
400 mm
A
0
400 mm
B
YP
<
1 of 1
>

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Step 1: Given data

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Step 2: Calculation of strain in the steel wire

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Step 3: Calculation of tension in the steel wire

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Step 4: Calculation of the applied load P needed to cause theta = 44.6°

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