The following data were obtained for a voltage measurement of the same sample on a noisy system:measurement #value (mv)11.221.0831.1641.1551.1861.1171.0881.25The average is 1.15125 and the standard deviation is 0.059626815635728If the slope of the calibration curve is 52.02 mV/ppm, what is the concentration detection limit?ppm (answer using 3 significant digits)D.L. =LLOQ=3sslope10sslope The following data were obtained for a voltage measurement of the same sample on a noisy system:measurement #value (mv)11.221.0831.1641.151.181.111.081.255678The average is 1.15125 and the standard deviation is 0.059626815635728If the slope of the calibration curve is 52.02 mV/ppm, what is the lower limit of quantitation?ppm (answer using 3 significant digits)D. L. =LLOQ=3sslope10sslope

1) Concentration of detection limit (D.L)/Limit of detection (LOD): It is the smallest concentration…

The average is 1.15125 and the standard deviation is 0.059626815635728 If the slope of the calibration curve is 52.02 mV/ppm, what is the lower limit of quantitation? ppm (answer using 3 significant digits) D. L. = LLOQ = 3s slope 10s slope

The average is 1.15125 and the standard deviation is 0.059626815635728 If the slope of the calibration curve is 52.02 mV/ppm, what is the lower limit of quantitation? ppm (answer using 3 significant digits) D. L. = LLOQ = 3s slope 10s slope

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter1: Introduction

Section: Chapter Questions

Problem 1.10QAP

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Question

The following data were obtained for a voltage measurement of the same sample on a noisy system:
measurement #value (mv)
1
1.2
2
1.08
3
1.16
4
1.15
5
1.18
6
1.11
7
1.08
8
1.25
The average is 1.15125 and the standard deviation is 0.059626815635728
If the slope of the calibration curve is 52.02 mV/ppm, what is the concentration detection limit?
ppm (answer using 3 significant digits)
D.L. =
LLOQ
=
3s
slope
10s
slope

The following data were obtained for a voltage measurement of the same sample on a noisy system:
measurement #value (mv)
1
1.2
2
1.08
3
1.16
4
1.15
1.18
1.11
1.08
1.25
5
6
7
8
The average is 1.15125 and the standard deviation is 0.059626815635728
If the slope of the calibration curve is 52.02 mV/ppm, what is the lower limit of quantitation?
ppm (answer using 3 significant digits)
D. L. =
LLOQ
=
3s
slope
10s
slope

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