The box-like Gaussian surface of the figure encloses a net charge of 20.0ε0 C and lies in an electric field given by E→=[(10.0+2.40x)i^−4.50j^+bzk^] N/C with x and z in meters and b a constant. The bottom face is in the xz plane; the top face is in the horizontal plane passing through y2 = 0.800 m. For x1 = 1.70 m, x2 = 3.80 m, z1 = 1.50 m, and z2 = 2.60 m, what is b?

The box-like Gaussian surface of the figure encloses a net charge of 20.0ε0 C and lies in an electric field given by E→=[(10.0+2.40x)i^−4.50j^+bzk^] N/C with x and z in meters and b a constant. The bottom face is in the xz plane; the top face is in the horizontal plane passing through y2 = 0.800 m. For x1 = 1.70 m, x2 = 3.80 m, z1 = 1.50 m, and z2 = 2.60 m, what is b?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

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The box-like Gaussian surface of the figure encloses a net charge of 20.0ε₀ C and lies in an electric field given by E→=[(10.0+2.40x)i^−4.50j^+bzk^] N/C with x and z in meters and b a constant. The bottom face is in the xz plane; the top face is in the horizontal plane passing through y₂ = 0.800 m. For x₁ = 1.70 m, x₂ = 3.80 m, z₁ = 1.50 m, and z₂ = 2.60 m, what is b?

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