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A: According to hardy Weinberg p²+ 2pq +q² = 1 p+q = 1 q = 0.4 0.6² +(2×0.6×0.4) +0.4²
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- Which of the following terms is the most broad? a phenotype b character c traitResults of Gergor Mendel's experiments with pea plants showed that heritable factors (genes) are particulate. Group of answer choices True FalseThe observable traits expressed by an organism are described as its _______. a. phenotype b. genotype c. alleles d. zygote
- The 8th graders used probability to obtain the gender of their offspring in a genetics task. The data is in the chart below. 28 Remembering that the mother has XX and the father has XY as their genotypes, why is the total of all the data more reasonable to analyze than the individual class data? Use reasoning from the chart to justify your explanation. Total Classes Boys Girls Offspring 9 8-A 44% 56% 4 8-B 56% 44% 6 7 8-C 86% 14% 2 5 8-D 29% 71% Total 17 15 32 B iU=: E E XAChi-Square analysis are often used by scientists. Find an example of a study where scientists used Chi-Square analysis and briefly describe how it was used. The example should be outside of gentics more like a real world example.A gene has two alleles, E and e. Another gene also has two alleles, T and t. Which of the following correctly shows linkage between the two genes? Group of answer choices ET/et Te/Et Ete/T Ee/tT
- population is black in colour but about 1/4 of them are white. gene (B) that produces an enzyme that converts a pigment molecule to produce the Black colour. There are 2 alleles of this gene - the dominant B and the recessive b. DNA analysis shows that black individuals have either a BB or Bb genotype and that white individuals have a bb phenotype. However, you have discovered that a small percentage of White individuals have either a BB or Bb genotype. Explain two reasons that could explain this apparent anomaly. They have a BB or Bb genotype but a white phenotype.4) The female dog has black fur. The male dog has black fur. Figure out the percentage or ratio of possible genotypes and phenotypes of their puppies by using the Punnett Square below. Place the alleles for the male parent below. One allele on each line: % of possible Genotypes: FF: Place the alleles for the female parent on the side. One allele on each line: Ff: ff. % of possible Phenotypes: Black fur: Grey fur: 5) The female dog is heterozygous. The male dog is heterozygous. Figure out the percentage or ratio of possible genotypes and phenotypes of their puppies by using the Punnett Square below. Place the alleles for the male parent below, One allele on each line: % of possible Geotypes: FF: Place the alleles for the female parent on the side. One allele on each line: Ff: ff: % of possible Phenotypes: Black fur: Grey fur:A scientist is studying a wild population of Japanese morning glories. It is easy to separate genotypes at a flower color locus by their phenotypes. Red individuals are homozygous for the R allele, yellow individuals are homozygous for the Y allele, and orange individuals are heterozygous. If the number of individuals with the following genotypes are: RR: 831 RY: 33 YY: 442 Is the population in Hardy Weinberg Equilibrium?
- What does it mean when an individual is found to be “homozygous” at a DNA profiling locus? They have three alleles at the locus They got different alleles from their mother and father They got the same alleles from their mother and father Their children got two alleles from them Their children got no alleles from themThis lab exercise requires that we count certain Mendelian traits among students present in the lab. Your professor will explain each trait being addressed and will then ask students to identify if they are dominant or recessive for that specific trait. The collected traits will then be plugged into the Hardy-Weinberg Equilibrium formula in order to calculate frequency of Homozygous dominant, Heterozygous and Homozygous recessive individuals in the same. p2 + 2pq + q2 = 100 given data: trait: hair swirl 19 individuals total. 10 had the homozygous dominant hair swirl trait: clockwise the nine other were recessive please do a step by step explanation with the calculation using this data, as I am very unfamiliar with what values mean what and the equation itself thank you!Many genetic disorders, such as cystic fibrosis and sickle-cell disease are due to mutations in a recessive allele. You have sampled an isolated population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate: 1g. the frequency of the recessive phenotype if "A" is completely dominant over "a” (round to the nearest hundredth)