The data below comes from a university that wanted to see if there was a relationship between High School GPA and College GPA. For each hypothesis test, provide the claim, critical values, test statistic and conclusion. 1) Using a 95% level of confidence, test the claim High School GPA's have a mean of 3.0.
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- Commercial Residential4.17 9.795.38 5.973.22 8.095.42 5.814.91 8.552.59 3.973.53 8.113.01 8.664.69 10.356.17 6.980.33 5.675.13 4.056.35 6.156.47 9.853.98 5.67Use the magnitudes (Richter scale) of the earthquakes listed in the data set below. Find the mean and median of this data set. Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier (data value that is very far away from the others) when considered in the context of the sample data given in this data set? Explain. Click the icon to view the earthquake Richter scale data. Find the mean and median of the data set using a calculator or similar data analysis technology. The mean of the data set is . (Round to three decimal places as needed.) The median of the data set is. (Round to three decimal places as needed.) Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier when considered in the context of the sample data given? O A. No, because this value is not very far away from all of the other data values. B. Yes, because this value is very far away from all of the other data values. O C. Yes, because this value is the maximum data value. O…2.42 1.44 2.05 0.24 2.78 2.6 2.69 1.02 1.44 1.21 2.85 0.91 1.54 0.37 1.07 0.04 2.41 2.79 1.25 0.63 1.63 2.57 0.01 0.54 0.81 1.81 2.27 0.64 1.65 2.72 0.58 1.68 2.56 2.82 0.17 0.29 1.65 0.18 1.61 0.79 2.33 2.15 2.73 2.93 0.14 2.21 2.16 5. Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.3 miles per hour. Speed (miles per hour) Frequency 42-45 46- 49 50 - 53 54 -57 58-61 22 12 The mean of the frequency distribution is (Round to the nearest tenth as needed.) miles per hour. Which of the following best discribes the relationship between the computed mean and the actual mean? A. The computed mean is not close to the actual mean because the difference between the means is more than 5%. O B. The computed mean is close to the actual mean because the difference between the means is less than 5%. O C. The computed mean is close to the actual mean because the difference between the means is more than 5%. D. The computed…
- A bank with branches located in a commercial district of a city and in a residential area has the business objective of developing an improved process for serving customers during the noon-to-1 P.M. lunch period. Management decides to first study the waiting time in the current process. The waiting time is defined as the number of minutes that elapses from when the customer enters the line until he or she reaches the teller window. Data are collected from a random sample of 15 customers at each branch. Complete parts (a) and (b) below. Click the icon to view the bank branch data. ... .. a. Assuming that the population variances from both banks are not equal, is there evidence of a difference in the mean waiting time between the two branches? (Use a = 0.1.) Let µ, be the mean waiting time of the commercial district branch and u, be the mean waiting time of the residential area branch. Determine the hypotheses. Choose the correct answer below. A. Ho: H1 = H2 H1: H1 # H2 В. Но: М 2 2 H1:…y 67.7 21.7 184.2 73.9 64.2 19.6 73.1 31.9 86.8 28 83.7 24.8 58.5 8.8 84.9 38.4 78.5 10.7 67.8 39.5 52.5 23.7 49 22 74.4 10 82 29.4 77.4 19.3 82.8 28 72.4 11.4 79 23.7 85.6 48.7 65.2 17.4 79.2 16.2 107.8 49 69.4 19.7 79.1 31.7 82.1 14.6 75.9 29.4 Make a scatter plot of this data. Which point appears to be an outlier? |(184.2,73.9) (Enter as an ordered pair.)WAIST BMI 120.4 33.3 107.8 28.0 120.3 45.4 97.2 28.4 95.1 25.9 112.0 31.1 78.0 20.1 103.5 32.7 89.7 25.8 112.0 36.5 95.0 25.8 115.3 34.5 118.8 37.4 92.6 26.1 75.5 19.3 101.8 29.9 92.5 27.4 100.8 31.4 82.8 21.0 92.9 28.5 120.4 30.8 107.8 31.2 120.3 33.6 97.2 26.7 95.1 24.5 112.0 21.6 78.0 27.4 103.5 29.3 89.7 24.6 112.0 29.1 78.8 23.2 65.8 19.4 114.4 38.9 78.0 21.0 106.8 33.3 112.4 31.8 94.8 27.3 90.6 21.6 95.2 27.1 71.5 20.0
- S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with Alzheimer's. She obtains a sample of n% = 30 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 26.2 with a standard deviation of s = 2.97. In the general population of Alzheimer's patients, the standardized test is known to have a population mean of p= 28.1. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following,…2.59 2.43 2.96 2.80 2.94 3.07 2.65 2.79 2.61 2.90 3.14 2.78 2.50 2.78 2.52 2.60 2.86 2.88 2.78 3.09 2.82 2.72 2.98 2.68 2.87 2.86 2.78 2.73 2.62 2.77 2.90 3.02 2.73 2.87 2.63 2.98 2.52 2.81 2.91 2.71 3.07 2.89 2.93 2.64 2.94 2.81 2.85 2.89 2.79 2.86 A school administrator believes that the mean class GPAs for a given course are higher than the preferred mean of 2.75 at a significance level of 0.05, and checks a randomly chosen sample of 50 classes. Create a histogram, and calculate x¯, the t-statistic, and the p-value. From the histogram, can normality be assumed? YES OR NO X= t= p= since the p-value ( GREATER THAN OR LESS THAN) the significance level 0.05, the null hypotheses is( fails to be rejected or is rejected) (sufficient or insufficient evidence) exist that the mean GPA is greater than 2.75.4.1 3.5 4.5 3.2 3.7 3.0 2.6 2.2 5.03.4 1.6 3.1 3.3 3.8 3.1 4.7 3.7 5.32.5 3.4 4.3 3.6 2.9 3.3 3.9 3.1 3.35.3 3.1 3.7 4.4 3.2 4.1 1.9 3.4 5.24.7 3.8 3.2 2.6 3.9 3.0 4.2 5.0 3.5 Using 6 class intervals, construct a a frequency distribution table
- 4.1 3.5 4.5 3.2 3.7 3.0 2.6 2.2 5.03.4 1.6 3.1 3.3 3.8 3.1 4.7 3.7 5.32.5 3.4 4.3 3.6 2.9 3.3 3.9 3.1 3.35.3 3.1 3.7 4.4 3.2 4.1 1.9 3.4 5.24.7 3.8 3.2 2.6 3.9 3.0 4.2 5.0 3.5 Set up a frequency distribution table with 6 class intervals1.542 1.585 1.532 1.466 1.499 1.611 1.598 1.498 1.6 1.504 1.545 1.558 1.622 1.466 1.546 1.494 1.548 1.626 1.555 1.712 1.442 1.443 1.699 1.701 1.44 1.608 1.52 1.478 1.542 1.511 1.698 1.88 1.11 1.21 1.987 1.39 1.459 1.533 1.532 1.523 1.397 1.487 Find a 99% CI on the mean tar content. Find the upper and lower limits.(Do not round off the values until you get the final answer)Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) x = 17.598 Sx = 16.01712719 n = 50 Click the icon to view a t distribution table. a. What is the number of degrees of freedom that should be used for finding the critical value t/2? Critical t values df = (Type a whole number.) t Distribution: Critical t Values Left tail Area In One Tall 0.005 0.01 0.025 0.05 0.10 Degrees of Area In Two Talls Degrees of Freedom 0.01 0.02 0.05 0.10 0.20 Freedom 1 63.657 31.821 12.706 6.314 3.078 1 9.925 6.965 4.303 2.920 1.886 3 5.841 4.541 3.182 2.353 1.638 3 4 4.604 3.747 2.776 2.132 1.533 4 4.032 3.365 2.571 2.015 1.476 6 3.707 3.143 2.447 1.943 1.440 6 7 3.499 2.998 2.365 1.895 1.415 7 3.355 2.896 2.306 1.860 1.397 Critical t value 3.250 2.821 2.262 1.833 1.383 (negat ive) 10 3.169 2.764 2.228 1.812 1.372 10 11 3.106 2.718 2.201 1.796 1.363 11 12 3.055 2.681 2.179 1.782 1.356 12 13 3.012…