The derivative of the function y = x(tan-'(3x))² is: y' tan (3x) 6x + (1+9x²) tan-³(3x)] tan (3x)[6x- (1+9x²) tan¬³(3x)]| 1+ 9x2 1+ 9x2 the above the above y' tan- (3x) 6x + (1+9x*) tan¬'(3x)] tan-(3x)[2x + (1+9x²) tan- (3x)] 1+ 3x y' = 1+ 9x the above the above none of them

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