The dissociation of molecular iodine into iodine atoms is represented as At 1000.0 K, the equilibrium constant K for the reaction is 3.80x 10 , Suppose you start with 0.0451 mol of L, in a 2.27 L flask at 1000.0 K, what are the 2. concentrations of the gases at equilibrium?

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter14: Chemical Equilibrium
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The dissociation of molecular iodine into iodine atoms is represented as
-D5
At 1000 0K, the equilibrium constant K for the reaction is 3.80× 10 °, Suppose you start with 0.0451 mol of L in a 2.27 L flask at 1000.0 K, What are the
concentrations of the gases at equilibrium?
Part 1 of 2
What is the equilibrium concentration of I,? Round your answer to 3 significant digits.
Part 2 of 2
What is the equilibrium concentration of 12 Round your answer to
significant digits.
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02022 McGrae Hili LLC All RIights Resanved Terms of Uke 1 Privecy Center
Acceasibility
37°F
8.
6.
Transcribed Image Text:The dissociation of molecular iodine into iodine atoms is represented as -D5 At 1000 0K, the equilibrium constant K for the reaction is 3.80× 10 °, Suppose you start with 0.0451 mol of L in a 2.27 L flask at 1000.0 K, What are the concentrations of the gases at equilibrium? Part 1 of 2 What is the equilibrium concentration of I,? Round your answer to 3 significant digits. Part 2 of 2 What is the equilibrium concentration of 12 Round your answer to significant digits. Check Save For Later Submit Assignment 02022 McGrae Hili LLC All RIights Resanved Terms of Uke 1 Privecy Center Acceasibility 37°F 8. 6.
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