The equation of the tangent line to the curve a? + y? = 49, at (9,-15) is15(x – 9) + 15Y =15(x + 9) – 159(x + 9) + 15159y =159(т — 9) — 1515

Name: The equation of the tangent line to the curve a? + y? = 49, at (9,-15
Uploaded: 2024-03-20T06:46:42.000Z
Channel: Bartleby
Description: The equation of the tangent line to the curve a? + y? = 49, at (9,-15) is15(x – 9) + 15Y =15(x + 9) – 159(x + 9) + 15159y =159(т — 9) — 1515

Answered: Image /qna-images/answer/fe7e6d69-0c79-4a1a-8c95-a8e5c7b85e96.jpg

Answered: The equation of the tangent line to the…

Math

Calculus

The equation of the tangent line to the curve z? + y² = 49, at (9,-15) is , %3D 15 - (z – 9) + 15 15 (x + 9) – 15 9 (x + 9) + 15 15 15 9 (x – 9) – 15 15

Trigonometry (MindTap Course List)

10th Edition

ISBN:9781337278461

Author:Ron Larson

Publisher:Ron Larson

Chapter6: Topics In Analytic Geometry

Section6.2: Introduction To Conics: parabolas

Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.

See similar textbooks

Similar questions

Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
Find all points (x, y) on the graph of y = x2 −6 with tangent lines passing through the point (3, 2); then find the equation of the tangent line corresponding to the smaller x-value.
Find an equation of the tangent line to the parabola y=x2+x such that it passes through the point (2, -3).
The slope of the tangent line at any point (x, y) on the curve 3x2 -2x+ 7 and the point (1. 3) is on the curve. What is the equation of the curve? 2y3x3 - х2 +7х-1 x3 x2 23 +7x - y= - 3 2 O y= x3 – x2 +7x-4 O y=3x3 - 2x2 +7x-5
Find the equations of all tangent lines to the curve x2 + 4y2 = 8 that pass through the point (-4, 0).
The slope of the tangent line to the parabola y = 2x + 2x + 6 at the point (- 1, 6) is: The equation of this tangent line can be written in the form y = mx + b where m is: and where b is:
Find an equation of a tangent line to the curve y = 3x³/2 + x2 at the point (1,5). Write you answer in y = mx +b form.
Find the points on the curve where tangents to the curve ²-2x³-4y+8= 0 pass through (1, 2).
Find the equation of the tangent line to the curve y = 1+x2 at the point (4, 9). The equation of this tangent line can be written 4x in the form y = mx + b. The equation of the tangent line is y =
Find all points on the curve y = x³ + 2x² - 6x +5 where the tangent is parallel to the line 2x + y = 4 O a. (-2/3,29/27) and (2.-17) O b. (2/3,-59/27) and (-1/2,17) (-2/3,29/27) and (-1/2,17) Oc. O d. none of these Oe. (2/3,59/27) and (-2,17)
Find the equation of a curve whose tangent line has slope 2x – 5 and the curve passes through the point ( 5 , 4 ).
Give the equation of the tangent which passes through the point with the coordinate x=2 of the parabola having the equation y – 1 = }(x + 2)².