The equilibrium constant for the reaction of decomposition of AB3 (AB3(g)= A(g) + 3B (g) is [A][B]³ K = [AB3] where [A], [B] and [AB3] are the concentrations of A, B and AB3 respectively. Use the properties of logarithms to obtain the -log[B] as a function of logK, log[A] and log[AB3].
The equilibrium constant for the reaction of decomposition of AB3 (AB3(g)= A(g) + 3B (g) is [A][B]³ K = [AB3] where [A], [B] and [AB3] are the concentrations of A, B and AB3 respectively. Use the properties of logarithms to obtain the -log[B] as a function of logK, log[A] and log[AB3].
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 50P
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![The equilibrium constant for the reaction of decomposition of AB3 (AB3(g)= A(g)+ 3B (g)) is
%3D
[A][B]³
K =
[AB3]
where [A], [B] and [AB3] are the concentrations of A, B and AB3 respectively.
Use the properties of logarithms to obtain the -log[B] as a function of logK, log[A] and log[AB3].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa912232-aaeb-4b92-923c-21dafd1ebf93%2Fbb29038f-111b-49e4-b7bd-e956b052eeb2%2Fmy2eduk_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant for the reaction of decomposition of AB3 (AB3(g)= A(g)+ 3B (g)) is
%3D
[A][B]³
K =
[AB3]
where [A], [B] and [AB3] are the concentrations of A, B and AB3 respectively.
Use the properties of logarithms to obtain the -log[B] as a function of logK, log[A] and log[AB3].
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