The equilibrium constant, Ke, for the following reaction is 4.04 x 104 at 428 K. PC15 (9) PC13 (g) + Cl₂ (g) When a sufficiently large sample of PC15 (9) is introduced into an evacuated vessel at 428 K, the equilibrium concentration of Cl₂(g) is found to be 0.185 M. Calculate the concentration of PC15 in the equilibrium mixture. [PC15] = M Submit Answer ques Retry Entire Group 9 more group attempts remaining

Chemistry: The Molecular Science
5th Edition
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Chapter12: Chemical Equilibrium
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Problem 60QRT
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80
F3
The equilibrium constant,
Ke, for the following reaction is
4.04 x 10-4 at 428 K.
PC15 (9) PC13 (9) + Cl2 (g)
When a sufficiently large sample of
PC1, (g) is introduced into an evacuated vessel at 428 K, the equilibrium concentration of
Cl₂ (g) is found to be 0.185 M.
Calculate the concentration of PC15 in the equilibrium mixture.
[PC15] =
Submit Answer
Q
F4
M
%
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[Review Topics]
[References]
Use the References to access important values if needed for this ques
Retry Entire Group 9 more group attempts remaining
0
F5
Cengage Learning Cengage Technical Support
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MacBook Air
C
F6
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F7
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F8
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F9
F10.
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Transcribed Image Text:80 F3 The equilibrium constant, Ke, for the following reaction is 4.04 x 10-4 at 428 K. PC15 (9) PC13 (9) + Cl2 (g) When a sufficiently large sample of PC1, (g) is introduced into an evacuated vessel at 428 K, the equilibrium concentration of Cl₂ (g) is found to be 0.185 M. Calculate the concentration of PC15 in the equilibrium mixture. [PC15] = Submit Answer Q F4 M % Show Hint [Review Topics] [References] Use the References to access important values if needed for this ques Retry Entire Group 9 more group attempts remaining 0 F5 Cengage Learning Cengage Technical Support < MacBook Air C F6 & F7 DII F8 DD F9 F10. I
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